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Ket [755]
2 years ago
5

What's carbon dioxide?

Mathematics
1 answer:
choli [55]2 years ago
4 0

Answer:

Carbon dioxide is a chemical compound composed of one carbon and two oxygen atoms. It is often referred to by its formula CO2. It is present in the Earth's atmosphere at a low concentration and acts as a greenhouse gas.

Step-by-step explanation:

There is also more to know about this. It's also a chemical.

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In one hour, a satellite orbiting the Earth travels 1.1 x 10 m (meters). Which
Fudgin [204]

Answer:

D because it be 1.1 * 109

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2 years ago
20POINTS Which exponential functions have been simplified correctly? Check all that apply. f (x) = 5 RootIndex 3 StartRoot 16 En
Rzqust [24]

Answer:

A, C, D.

Step-by-step explanation:

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3 years ago
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Savatey [412]

Answer:

B

Step-by-step explanation:

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5 0
2 years ago
A company wants to decrease their energy use by 16%.if their electric bill currently 2,2000 a month what will their be if they a
lyudmila [28]

The bill will be 18,480 if they are successful.

Step-by-step explanation:

Given,

Current bill of company = 22000

Energy usage to decrease = 16%

Amount of decreased usage = 16% of current bill

Amount of decreased usage = \frac{16}{100}*22000

Amount of decreased usage = 0.16*22000

Amount of decreased usage = 3520

Bill after decreased usage = Current bill - Amount of decreased usage

Bill after decreased usage = 22000 - 3520 = 18480

The bill will be 18,480 if they are successful.

Keywords: percentage, subtraction

Learn more about subtraction at:

  • brainly.com/question/10552347
  • brainly.com/question/10570041

#LearnwithBrainly

8 0
3 years ago
What is the 23rd term of the arithmetic sequence where a1 = 8 and a9 = 48?
joja [24]

Answer:

23rd term of the arithmetic sequence is 118.

Step-by-step explanation:

In this question we have been given first term a1 = 8 and 9th term a9 = 48

we have to find the 23rd term of this arithmetic sequence.

Since in an arithmetic sequence

T_{n}=a+(n-1)d

here a = first term

n = number of term

d = common difference

since 9th term a9 = 48

48 = 8 + (9-1)d

8d = 48 - 8 = 40

d = 40/8 = 5

Now T_{23}= a + (n-1)d

= 8 + (23 -1)5 = 8 + 22×5 = 8 + 110 = 118

Therefore 23rd term of the sequence is 118.

4 0
3 years ago
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