Answer:

And we can set equal this derivate to 0 in order to find the critical point and we got:


And we can calculate the second derivate and we got:

So then w can conclude that the value of t = 3.4375 represent the minimum value for the function and we can replace in the original function and we got:

So then the minimum annual income occurs at t = 3.43 (between 2008 and 2009) and the value is 25.094
Step-by-step explanation:
For this case we have the following function:

Where P represent the annual net income for the period 2007-2011 and 
And t represent the time in years since the start of 2005
In order to find the lowet income we need to use the derivate, given by:

And we can set equal this derivate to 0 in order to find the critical point and we got:


And we can calculate the second derivate and we got:

So then w can conclude that the value of t = 3.4375 represent the minimum value for the function and we can replace in the original function and we got:

So then the minimum annual income occurs at t = 3.43 (between 2008 and 2009) and the value is 25.094
12% of 16.50 = 1.98
16.50 + 1.98 = $18.48
Answer:
- Question (2): 1/6 ≈ 0. 17
Explanation:
<u>1. Arrange the information of the balls contained in the bowls in a table:</u>
Bowl X Bowl Y Bowl Z Total
Red balls 2 2 1 5
White balls 2 1 3 6
Blue balls 3 1 2 6
==============================
Totals 7 4 6 17
<u>2. To answer each question use the basic definition of probabilities</u>
- Probability = # of favorable events / # of possible events
<u>3. Question (1) If the ball is blue, what is the probability that it was drawn from bowl X? </u>
<u />
- Number of total blue balls: 6
- Number of blue balls in the bowl X: 3
- Probability that a ball that is blue was drawn from the bowl X: P (b/X)
P (b/X) = number of blue balls in the bowl X / total number of blue balls = 3 / 6 = 1/2 = 0.5
<u>4. Question (2) If the ball is either blue or white, what is the probability that it was drawn from bowl Y?</u>
- Number of total blue and white balls: 6 + 6 = 12
- Number of blue balls and white balls in the bowl Y: 1 + 1 = 2
- Probability that a ball that is either blue or white was drawn from the bowl Y: P (b or w / Y)
P (b or w /Y) = number of blue balls and white balls in the bowl Y / total number of blue balls and white balls = 2 / 12 = 1/6 ≈ 0.17