A jump discontinuity occurs when the limits as x approaches a number from the left and right are not equal. Basically, the graph "jumps" from one number to another at that x value.
A point discontinuity occurs when limits as x approaches a number from the left and right are equal, but the actual value of f(x) at x is not equal to the limit. Basically, a point is missing and there is a "hole" in the graph at that x value.
Looking at your graph, you can see that at x=0, the graph "jumps" from a value of 2 as the graph approaches x=0 from the left to a value of 1 as the graph approaches x=0 from the right. That means there is a jump discontinuity at x=0.
You can also see that there is a "hole" in the graph at x=-2 and x=8 as seen by the open circle. There is no hole at x=3 because the circle is filled in. That means there is a point discontinuity at x=-2 and x=8.
Your answer is B) jump discontinuity at x=0; point discontinuities at x=-2 and x=8.
Answer: The estimate is greater than the actual mass.
Answer:
Step-by-step explanation:
let t= time in seconds, h=height in ft
height at 
=
Velocity,v=
Height=
Therefore height after 
is obtained by adding height gained to initial height.
Answer:
Step-by-step explanation:
You are given the equation
y=7.27x+660, and you are given an x value of 165 so you just substitute that value into the equation for x
y=7.27(165)+660
y=1199.55+660
y=1859.55
Which is 1860ft when rounded to nearest whole number
Answer:
H' = (-5, 0)
I' = (6, -3)
Step-by-step explanation:
Since you are reflecting the line segment across the y- axis, the rule would be (x, y) ---> (-x, y). So, applying the rule to H first, all you would need to do is change the sign of positive 5 to -5. And since the rule doesn't have the y- value change, it will stay the same as 0. So H' = (-5, 0)
Then onto I', you would apply the same rule to just the x- value, since according to the rule, the y-value doesn't get changed. So that would be turning -6 into a positive 6, this is because a negative × a negative = a positive.
