Answer:
The probability that 8 mice are required is 0.2428.
Step-by-step explanation:
Given : A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.
To find : What is the probability that 8 mice are required? The probability that that 8 mice are required is nothing ?
Solution :
Applying binomial distribution,

Where, p is the probability of success 
q is the probability of failure q=1-p, 
n is total number of trials n=8
r=3
Substitute the values,




Therefore, the probability that 8 mice are required is 0.2428.
Zero is not less than nor equal to negative six.
Answer:
The product of 8/3 and 6/5/is greater than 8/3.
Step-by-step explanation:
(8/3)*(6/5) = (8*6)/(3*5) = 48/15
16/5. = 3.2 and 8/3 = 2.7
Answer:
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Step-by-step explanation: