X^2+y^2 = 16
can be written as
(x-0)^2+(y-0)^2 = 4^2
We see that the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2
where
(h,k) = (0,0) is the center
r = 4 is the radius
The polar form of the equation is simply r = 4. Why is this? Because the radius is fixed to be 4 no matter what happens with theta. As theta goes from 0 to 360, the points generated all form a circle centered at (0,0) with radius 4.
Answer: r = 4
Answer:
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Solve the following system using elimination:
{7 x + 2 y = -19 | (equation 1)
{2 y - x = 21 | (equation 2)
Add 1/7 × (equation 1) to equation 2:
{7 x + 2 y = -19 | (equation 1)
{0 x+(16 y)/7 = 128/7 | (equation 2)
Multiply equation 2 by 7/16:
{7 x + 2 y = -19 | (equation 1)
{0 x+y = 8 | (equation 2)
Subtract 2 × (equation 2) from equation 1:
{7 x+0 y = -35 | (equation 1)
{0 x+y = 8 | (equation 2)
Divide equation 1 by 7:
{x+0 y = -5 | (equation 1)
{0 x+y = 8 | (equation 2)
Collect results:
Answer: {x = -5, y = 8
Answer:
Sam is correct.
Step-by-step explanation:
Exponent rules state that when an number with an exponent is raised to a power, the two exponents multiply. For example, a^2^2=a^4.
The answer is the second option given
