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vitfil [10]
3 years ago
13

A zoo has 60 penguins total. If the Emperor penguins make up 35% of all of the penguins at the zoo, how many Emperor penguins ar

e at the zoo?
Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
5 0

Answer:

There are 21 emperor penguins at the zoo

Step-by-step explanation:

The total number of penguins in the zoo = 60

The percentage share of emperor penguin in the total population of penguin = 35 %

Number of emperor penguins at the zoo

\frac{35}{100} * 60

0.35 * 60

= 21

There are 21 emperor penguins at the zoo

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If f(x) = х2 – 2х + 3, thеn find<br> f(-3).
exis [7]

Answer:

\huge\boxed{\sf f(-3) = 18}

Step-by-step explanation:

\sf f(x) = x^2 - 2x + 3

<u>Put x = -3</u>

\sf f(-3) = (-3)^2 -2(-3) + 3\\f(-3) = 9 + 6 + 3\\f(-3) = 18

3 0
3 years ago
What is another way to write 1 1/2
FinnZ [79.3K]
1.5 and 3/2. 1.5 because 1/2 is equal to 0.5. 3/2 because it can be converted into an improper fraction
7 0
3 years ago
Read 2 more answers
Four more than three times a number, is less than 30. Which of the following is not a solution?
Tasya [4]
12.
12x3 is already 36, more than 30..
7 0
2 years ago
Read 2 more answers
:)
vitfil [10]

Answer:

45-(-15)

430-(-180)

11,560-(-185)

Step-by-step explanation:

just add the two numbers together for diffrence.

6 0
2 years ago
For a certain​ candy, 15​% of the pieces are​ yellow, 1010​% are​ red, 2020​% are​ blue, 55​% are​ green, and the rest are brown
MatroZZZ [7]
A) the probability it is brown would be 50%; the probability it is yellow or blue would be 35%; the probability it is not green is 95%; the probability it is striped is 0%.
B) the probability of all brown would be 12.5%; the probability that the third one is the first red one drawn is 8.1%; the probability that none are yellow is 61.4%; the probability that at least one is green is 14.3%.

Explanation:
A) The probability that it is brown is the percentage of brown we have.  Brown is not listed, so we subtract what we are given from 100%:
100-(15+10+20+5) = 100-(50) = 50%.  The probability that one drawn is yellow or blue would be the two percentages added together:  15+20 = 35%.  The probability that it is not green would be the percentage of green subtracted from 100:  100-5=95%.  Since there are no striped candies listed, the probability is 0%.
B) Since we have an infinite supply of candy, we will treat these as independent events.  All 3 being brown is found by taking the probability that one is brown and multiplying it 3 times:
0.5*0.5*0.5 = 0.125 = 12.5%.  
To find the probability that the first one that is red is the third one drawn, we take the probability that it is NOT red, 100-10 = 90% = 0.9, for the first two, and the probability that it IS red, 10% = 0.1, for the last:
0.9*0.9*0.1 = 0.081 = 8.1%.

The probability that none are yellow is found by raising the probability that the first one is not yellow, 100-15=85%=0.85, to the third power:

0.85^3 = 0.614 = 61.4%.

The probability that at least one is green is computed by subtracting 1-(probability of no green).  We first find the probability that all three are NOT green:
0.95^3 = 0.857375
1-0.857375 = 0.143 = 14.3%.
3 0
3 years ago
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