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slavikrds [6]
3 years ago
12

Select the correct answer. Which if the following statements is an example of a good problem statement? to design a pair of runn

ing shoes for women B. to design a pair of shoes OC. to design footwear OD to design a white pair of running shoes with laces and one inch sole for​
Engineering
1 answer:
algol133 years ago
5 0

Answer:

To design a pair of running shoes for women.

Explanation:

A good problem statement will led a reader from a shared context to understanding of a problem and on to a proposed solution.

The elements of a good problem statement are ;

  • It should be addressing a gap in an idea
  • It should be vital enough to contribute to an existing body of research
  • It should offer room for further research
  • It should give itself to investigation through data collection.
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The throttling valve is replaced by an isentropic turbine in the ideal vapor-compression refrigeration cycle to make the ideal v
Zarrin [17]

Answer:

False

Explanation:

The given statement is False. In real scenario the throttling valve not replaced by an isentropic turbine in the ideal vapor-compression refrigeration cycle. It is done so that the ideal vapor-compression refrigeration cycle to make the ideal vapor-compression refrigeration cycle more closely approximate the actual cycle.

4 0
3 years ago
An engine operates on gasoline (LHV=44 MJ/kg) with a brake thermal efficiency of 37.9 % What is the brake specific fuel consumpt
scZoUnD [109]

Answer:

s =0.21\ kg/Kw.hr

Explanation:

Given that

Calorific value (CV) = 44 MJ/Kg

CV= 44,000 KJ/kg

Brake thermal efficiency(η) = 37.9 %

We know that

\eta =\dfrac{BP}{\dot{m_f}\times CV}

Where BP is the brake power

\eta =\dfrac{BP}{\dot{m_f}\times CV}

0.379 =\dfrac{BP}{\dot{m_f}\times 44000}

\dfrac{BP}{\dot{m_f}}=16676

Brake specific fuel consumption (s)

s =\dfrac{\dot{m_f}}{BP}

s =\dfrac{3600\times \dot{m_f}}{BP}

s =\dfrac{3600}{16,676}\ kg/Kw.hr

s =0.21\ kg/Kw.hr

7 0
3 years ago
Question 1
vlabodo [156]

Answer:

A. from zero at the center to maximum at the circumference.

Explanation:

The shear stress describes the process where a body deforms as a result of a part sliding over the other.

The value of shear stress which is induced in the shaft due to the applied couple varies from zero at the center to maximum at the circumference.

The shear stress in a shaft is given by this formula;

τ = Tr/I

where;

τ = shear stress (MPa).

T = applied torque (Nmm).

r = distance from center to stressed surface in the given position (mm).

I = polar moment of Inertia of cross-sectional area (mm).

3 0
3 years ago
A and B connect the gear box to the wheel assemblies of a tractor, and shaft C connects it to the engine. Shafts A and Blie in t
azamat

Answer:

The couples are not all on one axis or plane for that matter but if the A and B connector had to be specified it would go by the yz axis diagonal to the x axis with a magnitude of about 15. The direction of the axis would be pointed up to the second quadrant. Hope this was helpful

Explanation:

8 0
4 years ago
A boiler is used to heat steam at a brewery to be used in various applications such as heating water to brew the beer and saniti
Natalija [7]

Answer:

net boiler heat = 301.94 kW

Explanation:

given data

saturated steam = 6.0 bars

temperature = 18°C

flow rate = 115 m³/h = 0.03194 m³/s

heat use by boiler = 90 %

to find out

rate of heat does the boiler output

solution

we can say saturated steam is produce at 6 bar from liquid water 18°C

we know at 6 bar from steam table

hg = 2756 kJ/kg

and

enthalpy of water at 18°C

hf = 75.64 kJ/kg

so heat required for 1 kg is

=hg - hf

= 2680.36 kJ/kg

and

from steam table specific volume of saturated steam at 6 bar is 0.315 m³/kg

so here mass flow rate is

mass flow rate = \frac{0.03194}{0.315}

mass flow rate m = 0.10139 kg/s

so heat required is

H = h × m  

here h is heat required and m is mass flow rate

H = 2680.36  × 0.10139

H =  271.75 kJ/s = 271.75 kW

now 90 % of boiler heat is used for generate saturated stream

so net boiler heat = \frac{H}{0.90}

net boiler heat = \frac{271.75}{0.90}

net boiler heat = 301.94 kW

5 0
3 years ago
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