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mote1985 [20]
3 years ago
5

How does the turbo on a car work?

Engineering
2 answers:
laila [671]3 years ago
6 0

Answer:

the exaust of the car spins an impeller in the turbo which causes the turbo o force air into the motor wala more power

Explanation:

Licemer1 [7]3 years ago
4 0

The turbocharger on a car applies a very similar principle to a piston engine. It uses the exhaust gas to drive a turbine. This spins an air compressor that pushes extra air (and oxygen) into the cylinders, allowing them to burn more fuel each second.
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If 9 + 10 = 21, then what is 10 + 10?
Katen [24]
The answer would be 23 because the engines in a horse is a amount of 9 engines in 69 cars
6 0
2 years ago
Read 2 more answers
A 1-w, 350-ω resistor is connected to 24 v. Is this resistor operating within its power rating?
seraphim [82]

Answer:

No.

Explanation:

P_r = Power rating = 1 W

R = Resistance = 350\ \Omega

V = Voltage = 24\ \text{V}

Power is given by

P=\dfrac{V^2}{R}\\\Rightarrow P=\dfrac{24^2}{350}\\\Rightarrow P=1.65\ \text{W}

1.65\ \text{W}>1\ \text{W}

So

P>P_r

Hence, the resistor is not operating within its power rating.

8 0
3 years ago
A coil consists of 200 turns of copper wire and have a cross-sectional area of 0.8 mmm square.The mean length per turn is 80 cm
pav-90 [236]

Answer:

The resistance of the coil is 4 Ω.

Explanation:

The resistance (R) of the coil can be calculated using the following equation:

R = \frac{\rho L}{A}

Where:

ρ: is the resistivity of copper = 0.02x10⁻⁶ Ωm

L: is the length of the coil

A: is the cross-sectional area = 0.8 mm² = 8x10⁻⁷ m²

The length of the coil is given by:

L = 200 turn* 80 cm/turn = 16000 cm = 160 m

Now, the resistance is:          

R = \frac{\rho L}{A} = \frac{0.02 \cdot 10^{-6} \Omega m*160 m}{8 \cdot 10^{-7} m^{2}} = 4 \Omega

Therefore, the resistance of the coil is 4 Ω.

                                       

I hope it helps you!

6 0
3 years ago
If gain of the critically damped system is increased, the system will behave as a) Under damped b) Over damped c) Critically dam
Ganezh [65]

Answer:

a) Under damped

Explanation:

Given that system is critically damped .And we have to find out the condition when gain is increased.

As we know that damping ratio given as follows

\zeta =\dfrac{C}{C_c}

Where C is the damping coefficient and Cc is the critical damping coefficient.

C_c=2\sqrt{mK}

So from above we can say that

\zeta =\dfrac{C}{2\sqrt{mK}}

\zeta \alpha \dfrac{1}{\sqrt K}

From above relationship we can say when gain (K) is increases then system will become under damped system.

7 0
3 years ago
Three capillary tubes with different radius (r1=1.0mm, r2=0.1mm, r3=0.01mm) are inserted into the same cup of water. The surface
kobusy [5.1K]

Answer:

you fgykyiihohuoououu

Explanation:

jjj

4 0
3 years ago
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