Answer:
The distance from the entrance at which the boundary layers meet is 0.516m
The distance from the entrance at which the thermal boundary layers meet is 1.89m
Explanation:
For explanation, look at the attached file
Answer:
Kindly check explanation
Explanation:
(a) μMN, (b) N/μm, (c) MN/ks2, and (d) kN/ms.
(a) μMN = (10^-6 * 10^6) = 10^(-6 + 6) = 10^0 = N
b) N/μm = N / 10^-6 m = 10^6 * N/m = MN/m
(c) MN/ks2 = 10^6N / (10^3 s)^2
10^6 N / 10^6s^2 = 10^6 * 10^-6 N /s^2 = N/s^2
D) kN/ms = 10^3N / 10^-3 s = 10^3 * 10^3 * N/s = 10^6N / s = MN/s
2)
a) 0.000431kg = 431 × 10^6 kg = 431 * 10^9g = 431Gg
b) 35.3 × 10^3 N
10^3 = kilo(K)
35.3 KN
C) 0.00532km = 5.32 * 10^3 km = 5.32 * 10^3 * 10^3 = 5.32 * 10^6 = 5.32Mm
3) Represent each of the following combinations of units in the correct SI form: (a) Mg/ms, (b) N/nm, and (c) mN/(kg⋅μs).
a) Mg/ms = 10^6g / 10^-3s = 10^6 * 10^3 g/s = 10^9 g/s = Gg/s
b) N/nm = N / 10^-9 m = 10^9 N/m = GN/m
c) mN/(kg⋅μs) = 10^6N / kg(10^-6s) = 10^12N/(kg.s)
= TN/(kg.s)
I am mostly on the side of compromise do i think that’s the answer
Answer:
Uair = 0.0749 KW/k = 74.9 W/k
Explanation:
The natural air change per hour is given by the formula:
Natural Air Change per Hour = ACPH = 60*Volume Flow/Volume
where,
ACPH = 0.4
Volume Flow = ? in ft³/min
Volume = 19456 ft³
Therefore,
0.4 = (60 min)(Volume Flow)/(19456 ft³)
Volume Flow = (0.4)(19456 ft³)/(60 min) = (129.7 ft³/min)(1 min/60 s)
Volume Flow = (2.16 ft³/s)(0.3048 m/1 ft)³ = 0.061 m³/s
Now, we find heat loss coefficient:
Uair = Volumetric Flow*Density of air*Specific Heat Capacity of air
Uair = (0.061 m³/s)(1.225 kg/m³)(1 KJ/kg.k)
<u>Uair = 0.0749 KW/k = 74.9 W/k</u>
Answer:
The voltage needed to accelerate the electron beam is 2.46 x 10^16 Volts
Explanation:
The rate of electron flow is given as:
q = 1015 electrons per second
The total current is given by:
Total Current = (Rate of electron flow)(Charge on one electron)
Total Current = I = (1015 electrons/s)(1.6 x 10^-19 C/electron)
I = 1.624 x 10^-16 A
Now, we know that electric power is given as:
Electric Power = Current x Voltage
P = IV
V = P/I
V = 4 W/1.624 X 10^-16 A
<u>V = 2.46 x 10^16 Volts</u>
