Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
Answer:
C.
Step-by-step explanation:
(f+g)(x) ➡ f(x) + g(x)
x/2 - 2 + 2x^2 + x - 3 = 2x^2 + 3x/2 -5
Answer:
21.4375
Step-by-step explanation:
213 because
4/15 * 315 = 84 male <span>
11/15 * 315 = 231 female
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