Answer:
P = 1/(sqrt(4)) and w = 1/(sqrt(9))
Step-by-step explanation:
Only the roots of perfect squares are rational numbers. 2, 3, 6, and 10 are not perfect squares, so their roots are irrational. Both 4 and 9 are perfect squares, so their roots are rational. The sum of rational numbers is a rational number.

Answer:
98
Step-by-step explanation:
4=x56×7
4=x392
392/4=X
98
You could rewrite

as

and be tempted to cancel out the factors of

. But this cancellation is only valid when

.
When

, you end up with the indeterminate form

, which is why

is not a zero.
You just solve for y.
y=<span><span><span>13/11</span>x</span>+<span>12/<span>11</span></span></span>
C I am soooo sorry if I’m wrong