How many atoms are in the outer-most shell in order for it to be stable?

Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th

mario62 [17]

Answer: The freezing point of solution is 2.6°C

Explanation:

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

where,

$\Delta T_f$ = $\text{Freezing point of pure solution}-\text{Freezing point of solution}$

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_f$ = molal freezing point depression constant = 5.12 K/m = 5.12 °C/m

$m_{solute}$ = Given mass of solute (anthracene) = 7.99 g

$M_{solute}$ = Molar mass of solute (anthracene) = 178.23 g/mol

$W_{solvent}$ = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

$5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC$

Hence, the freezing point of solution is 2.6°C

8 0

3 years ago

Consider the conversion of 2-naphthol and 1-bromobutane into an ether via the williamson ether synthesis. list the procedural st

Lemur [1.5K]

Answer:

Following are the solution to this question:

Explanation:

Please find the complete question in the attachment.

Start of Laboratory

Dissolve 2-naphthol in the round bottom flask with ethanol.

Add pellets of sodium hydroxide and hot chips. Attach a condenser.

Heat for 20 minutes under reflux, until the put a burden dissolves.

After an additional hour, add 1-Bromobutane and reflux.

Pour the contents into a beaker with ice from a round bottom flask.

On a Bachner funnel, absorb the supernatant by vacuum filtration.

Utilizing cold water to rinse the material and dry that on the filter.

Ending of the Lab

6 0

3 years ago

1. What is the molarity of a solution which contains 0.256 mol of a substance dissolved in 143 mL of solution.

LenaWriter [7]

Answer:

The equation for molarity is moles/liter for the first question you would do 0.256/0.143 liters to get 1.790 mol/L

Explanation:

The second problem you would do need to find the moles of NaCl which you would do by doing 4.89 g/58.44g/mol= 0.08367 then do 0.08367/0.600= 0.139 mol/L

The third problem would be the same steps as the second one.

The fourth problem would be (0.460M)(5.50L)= 2.53 moles

4 0

3 years ago

How many total electrons can be contained in the 4d sublevel? 2 6 10 14

qaws [65]

The s sublevel has just one orbital, so can contain 2 electrons max. The p sublevel has 3 orbitals, so can contain 6 electrons max. The d sublevel has 5 orbitals, so can contain 10 electrons max. And the 4 sublevel has 7 orbitals, so can contain 14 electrons max.
So, having this in mind, 10 electrons in total can be contained in the 4d sublevel.

5 0

4 years ago

Read 2 more answers

1.5 moles are present in 60.0 grams of calcium.

Andrew [12]

Answer:

True.

Explanation:

To know which option is correct, let us calculate the number of mole present in 60g of calcium. This is illustrated below:

Mass of Ca = 60g

Molar Mass of Ca = 40g/mol

Number of mole Ca =....?

Number of mole = Mass/Molar Mass

Number of mole of Ca = 60/40

Number of mole Ca = 1.5 moles.

From the calculations made above, we can see that 1.5 moles are present in 60.0 grams of calcium

3 0

3 years ago