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Gre4nikov [31]
3 years ago
12

The heat of fusion for ice is 334 joules per gram. Adding 334 joules of heat to one gram of ice at STP will

Chemistry
1 answer:
yulyashka [42]3 years ago
3 0

C) change to water at the same temperature

Explanation:

Adding 334Joules of heat to one gram of ice at STP will cause ice to change to water at the same temperature.

  • The heat of fusion is the amount of energy needed to melt a given mass of a solid
  • It is also conversely the amount of energy removed from a substance to freeze it.
  • The addition of this energy does not cause a decrease or increase in temperature.
  • Only a phase change occurs.

Learn more:

Heat of fusion brainly.com/question/4050938

#learnwithBrainly

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Match the element with number of valence electrons
Alla [95]

Answer:

Oxygen-O = 6

Carbon C = 4

Gallium G = 3

Astatine A = 7

Arsenic As = 5

Potassium K = 1

Hydrogen H = 1

Helium H = 2

Explanation:

6 0
2 years ago
How many moles of water are in a beaker with 50 mL?
tatiyna

Answer:

Number of moles = 2.8 mol

Explanation:

Given data:

Number of moles of water = ?

Volume of water = 50 mL

Density of water = 1.00 g/cm³

Solution:

1 cm³ =  1 mL

Density = mass/ volume

1.00 g/mL = mass/ 50 mL

Mass = 1.00 g/mL× 50 mL

Mass = 50 g

Number of moles of water:

Number of moles = mass/molar mass

Number of moles = 50 g / 18 g/mol

Number of moles = 2.8 mol

5 0
3 years ago
Which items are directly related to radioactive decay
uranmaximum [27]
E=mc^2 and mass defect
3 0
3 years ago
In Part A, we saw that the theoretical yield of aluminum oxide is 1.60 mol . Calculate the percent yield if the actual yield of
garri49 [273]

Taking into account definition of percent yield, the percent yield for the reaction is 76.25%.

<h3>Percent yield</h3>

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield=\frac{actual yield}{theorical yield}x100

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

<h3>Percent yield in this case</h3>

In this case, you know:

  • actual yield= 1.22 mol
  • theorical yield= 1.60 mol

Replacing in the definition of percent yields:

percent yield=\frac{1.22 mol}{1.60 mol}x100

Solving:

<u><em>percent yield= 76.25%</em></u>

Finally, the percent yield for the reaction is 76.25%.

Learn more about percent yield:

brainly.com/question/14408642

#SPJ1

4 0
1 year ago
If 9.5 × 10²⁵ molecules of CO₂ are produced in a combustion reaction, what is the mass in kg of CO₂ that is produced?
Leno4ka [110]

Answer:

6.9428 kg of CO2

Explanation:

1) Use Avogadro's number that states 1 mole = 6.022 x 10^23 particles. Convert 9.5 x 10^25 molecules into moles.

9.5 x 10^25 CO2 moleculesx\frac{1 mole CO2}{6.022 x 10^23} = 157.75 moles CO2

2) Convert 157.75 moles of CO2 into grams. CO2's molar mass is 44.01g.

157.75moles CO2 x \frac{44.01g/mol}{1 mole CO2} = 6942.79g

3) Convert 6942.79 grams into kilograms (divide by 1000):

6.9428 kg

4 0
2 years ago
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