Answer:
8.08 × 10⁻⁴
Explanation:
Let's consider the following reaction.
COCl₂(g) ⇄ CO (g) + Cl₂(g)
The initial concentration of phosgene is:
M = 2.00 mol / 1.00 L = 2.00 M
We can find the final concentrations using an ICE chart.
COCl₂(g) ⇄ CO (g) + Cl₂(g)
I 2.00 0 0
C -x +x +x
E 2.00 -x x x
The equilibrium concentration of Cl₂, x, is 0.0398 mol / 1.00 L = 0.0398 M.
The concentrations at equilibrium are:
[COCl₂] = 2.00 -x = 1.96 M
[CO] = [Cl₂] = 0.0398 M
The equilibrium constant (Keq) is:
Keq = [CO].[Cl₂]/[COCl₂]
Keq = (0.0398)²/1.96
Keq = 8.08 × 10⁻⁴
Answer: 0.25 mol
Explanation:
Use the formula n=N/NA
n= number of mols
N = number of particles
Nᵃ = Avogadros constant = 6.02 x
So, n=
The 10 to the power of 23 cancels out and you are left with 1.505/6.02, which is approximately 1/4. This is the same as 0.25 mol.
Hope this helped :)
Answer: The new concentration of a solution of 
is 0.2 M 10.0 mL of a 2.0 M solution is diluted to 100 mL.
Explanation:
Given: 
= 10.0 mL, 
= 2.0 M
= 100 mL, 
= ?
Formula used to calculate the new concentration is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that the new concentration of a solution of is 0.2 M 10.0 mL of a 2.0 M solution is diluted to 100 mL.
The hydrogen ion concentration [H3O+] in an egg white containing 6.3 × 10-⁷M of [OH-] is 1.5 × 10-⁸M.
<h3>How to calculate [H3O+]?</h3>
The hydrogen ion concentration of a solution can be calculated as follows:
pOH = - log [OH-]
pOH = - log [6.3 × 10-⁷M]
pOH = - [-6.2]
pOH = 6.2
Since pOH + pH = 14
pH = 14 - 6.2
pH = 7.8
pH = - log [H3O+]
7.8 = - log [H3O+]
[H3O+] = 10-⁷:⁸
[H3O+] = 1.5 × 10-⁸M
Therefore, the hydrogen ion concentration [H3O+] in an egg white containing 6.3 × 10-⁷M of [OH-] is 1.5 × 10-⁸M.
Learn more about hydrogen ion concentration at: brainly.com/question/15082545
D an example of polygenic inheritance
ps this is more biology than chemistry
