I think this is the answer
Answer:
13.2 g Na2CO3
Explanation:
Convert 10.0 g NaOH to mol.
10.0 g x 1 mol/39.997 g = 0.250 mol
Use mol ration given by the equation: 2 mol NaOH to 1 mol Na2CO3
0.250 mol NaOH x 1 mol Na2CO3/2 mol NaOH = 0.125 mol Na2CO3
Finally, convert the moles of Na2CO3 to grams.
0.125 mol Na2CO3 x 105.99 g/1 mol = 13.2 g
1Liter = 1000ml,
Start with the given 25liter X 1000milleters/ 1liters = 25000ml or 2.5X10^4ml
Remember to Cancel the unit...
1
mol of lithium bromide has a mass of
86.85
g
⋅
m
o
l
−
1
. You have
2.6
moles of the stuff.
Explanation:
So mass
=
86.85
g
⋅
m
o
l
−
1
×
2.6
m
o
l
=
?
?
g
.
