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3 years ago

Which of the following is not a trend that varies systematically in the periodic table

Chemistry

2 answers:

UNO [17]3 years ago

5 0

Answer:

B: Symbols of Elements

Explanation:

juin [17]3 years ago

3 0

Answer: B: Symbols of Elements

Explanation:

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In a polyatomic ion, the -ate ending indicates one ____ oxygen than the -ite ending. A. more B. cannot be determined C. less D.

Aneli [31]

Correct answer is A: more :)

4 0

3 years ago

A student decomposed 3.67g of copper (ii) hydroxide into copper (ii) oxide. how many ml of 3m h2so4 is need to react with all th

vredina [299]

In the presence of heat, copper (II) hydroxide decomposes in to copper (II) oxide.
Cu(OH)₂ (s) ----> CuO (s) + H₂O (l)
upon decomposition, water is removed from Cu(OH)₂
the amount of Cu(OH)₂ decomposed - 3.67 g
number of moles of Cu(OH)₂ - 3.67 g / 97.5 g/mol = 0.038 mol
stoichiometry of Cu(OH)₂ to CuO is 1:1
therefore number of CuO moles formed are - 0.038 mol
CuO reacts with sulfuric acid to form CuSO₄
CuO + H₂SO₄ ---> CuSO₄ + H₂O
stoichiometry of CuO to H₂SO₄ is 1:1
therefore number of H₂SO₄ moles that should react is 0.038 mol
the molarity of H₂SO₄ is 3M
this means that in 1000 ml - 3 mol of H₂SO₄ present
so if 3 mol are present in 1000 ml
then volume for 0.038 mol = 1000/3 * 0.038
= 12.67 ml

6 0

4 years ago

4. How many electrons are in the electron shell closest to the nucleus?

Roman55 [17]

Answer:

Explanation:

there are 2 electrons close to the nucleus

5 0

3 years ago

Read 2 more answers

The reaction 3 BrO- (aq) --> BrO3- (aq) + 2 Br - (aq) in basic solution is second order in BrO-(aq) with a rate cons

Phoenix [80]

Answer:

0.124 M

Explanation:

The reaction obeys second-order kinetics:

$r = k[BrO^-]^2$

According to the integrated second-order rate law, we may rewrite the rate law in terms of:

$\dfrac{1}{[BrO^-]_t} = kt + \dfrac{1}{[BrO^-]_o}$

Here:

$k$ is a rate constant,

$[BrO^-]_t$ is the molarity of the reactant at time t,

$[BrO^-]_o$ is the initial molarity of the reactant.

Converting the time into seconds (since the rate constant has seconds in its units), we obtain:

$t = 1.00 min = 60.0 s$

Rearranging the integrated equation for the amount at time t:

$[BrO^-]_t = \dfrac{1}{kt + \dfrac{1}{[BrO^-]_o}}$

We may now substitute the data:

$[BrO^-]_t = \dfrac{1}{0.056 M^{-1}s^{-1}\cdot 60.0 s + \dfrac{1}{0.212 M}} = 0.124 M$

7 0

3 years ago

Let's say we have 2 Zinc atoms and 2 Sulfur atoms on one side of the equation. According to the Law of Conversation and Mass, ho

Viefleur [7K]

Answer:

Two

Explanation:

The law of conservation of mass states that in an isolated system the mass present is neither destroyed nor created by chemical changes or physical changes.

This tells us that the mass of reactants must be equal to the product mass.

If 1 atom of Zn react with one atoms of sulfur, the product will be 1 molecule of zinc sulfide according to the equation below

Zn(s) + S(s) ⇒ ZnS(s)

therefore two atoms each f zinc and sulfur will product two molecules of Zn sulfide

5 0

3 years ago