Answer:
The mass of CO in 12,000 Liters of air is
.
Explanation:
The ppm is the amount of solute (in milligrams) present in one Liter of a solvent. It is also known as parts-per million.
To calculate the ppm of oxygen in sea water, we use the equation:

The ppm concentration of CO = 10 ppm
Mass of CO = m
Volume of air = 12,000 L


The mass of CO in 12,000 Liters of air is
.
Answer:
Explanation:
The water table or phreatic surface
Answer:
Velocity, u = 14.7 m/s
Explanation:
It is given that, a driver can probably survive an acceleration of 50 g that lasts for less than 30 ms, but in a crash with a 50 g acceleration lasting longer than 30 ms, a driver is unlikely to survive.
Let v is the highest speed that the car could have had such that the driver survived. Using a = -50 g and t = 30 ms
Using first equation of kinematics as :

In case of crash the final speed of the driver is, v = 0
u = 14.7 m/s
So, the highest speed that the car could have had such that the driver survived is 14.7 m/s. Hence, this is the required solution.
Answer:
Explanation:
1 . Write the chemical equation.
2 . Calculate the moles of product from the first reactant.
3 . Calculate the moles of product from the second reactant.
4 . Identify the limiting reactant and the excess reactant.
5 . Calculate the mass of excess reactant used up.
6 . Calculate the mass of unused excess reactant.
7 . Calculate the mass of limiting reactant needed to react with the 8 . unused excess reactant.