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ziro4ka [17]
3 years ago
11

Can someone help me please

Chemistry
2 answers:
kvasek [131]3 years ago
6 0

Answer:

D

Explanation:

John is not a very good businessman.

:D

Paladinen [302]3 years ago
6 0
D

Hopes This helps !!!
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How many milligrams of CO exist in 12000 liters of air with 10 ppm of CO?
VARVARA [1.3K]

Answer:

The mass of CO in 12,000 Liters of air is 12\times 10^4 mg.

Explanation:

The ppm is the amount of solute (in milligrams) present in one Liter of a solvent. It is also known as parts-per million.

To calculate the ppm of oxygen in sea water, we use the equation:

\text{ppm}=\frac{\text{Mass of solute}(mg)}{\text{Volume of solution}(L)}

The ppm concentration of CO = 10 ppm

Mass of CO = m

Volume of air = 12,000 L

10 =\frac{m}{12,000 L}

m=10\times 12,000 mg=120,000 mg=12\times 10^4 mg

The mass of CO in 12,000 Liters of air is 12\times 10^4 mg.

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3 years ago
The top of the saturated zone of soil or rocks is called the
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Answer:

Explanation:

The water table or phreatic surface

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4 years ago
Naturally occurring boron (B) contains 80.0% 11B (11.01 amu) and 20.0% 10B (10.01 amu). Calculate the average atomic mass of bor
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3 years ago
In a car crash, large accelerations of the head can lead to severe injuries or even death. A driver can probably survive an acce
Alexxandr [17]

Answer:

Velocity, u = 14.7 m/s

Explanation:

It is given that, a driver can probably survive an acceleration of 50 g that lasts for less than 30 ms, but in a crash with a 50 g acceleration lasting longer than 30 ms, a driver is unlikely to survive.

Let v is the highest speed that the car could have had such that the driver survived. Using a = -50 g and t = 30 ms

Using first equation of kinematics as :

v=u+at

In case of crash the final speed of the driver is, v = 0

0=u+at

-u=at

-u=-50\times 9.8\times 30\times 10^{-3}

u = 14.7 m/s

So, the highest speed that the car could have had such that the driver survived is 14.7 m/s. Hence, this is the required solution.

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3 years ago
If 21.8 g of NO and 13.8 g of O2 are used to form NO2, how many
mario62 [17]

Answer:

Explanation:

1 . Write the chemical equation.

2 . Calculate the moles of product from the first reactant.

3 . Calculate the moles of product from the second reactant.

4 . Identify the limiting reactant and the excess reactant.

5 . Calculate the mass of excess reactant used up.

6 . Calculate the mass of unused excess reactant.

7 . Calculate the mass of limiting reactant needed to react with the 8 .  unused excess reactant.

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3 years ago
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