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Karo-lina-s [1.5K]

4 years ago

5

When NADH donates two electrons to ubiquinone during respiration, ubiquinone isa. reduced.b. oxidized.c. phosphorylated.d. aerob

ic.e. hydrolyzed.

1 answer:

olga nikolaevna [1]4 years ago

5 0

Reduced ... more electrons gain is a reduction

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qwelly [4]

SO2 is a polar molecule because Oxygen gains more electrons making one side more negative than the other.

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4 years ago

How many grams are in 26 moles of<br> magnesium hydroxide?

WINSTONCH [101]

1,516.31168 grams of Magnesium Hydroxide

3 0

3 years ago

Calculate the mass percent (m/m) of a solution prepared by dissolving 45.09 g of NaCl in 174.9 g of H2O.

inysia [295]

Answer:

20.3 % NaCl

Explanation:

Given data:

Mass of solute = 45.09 g

Mass of solvent = 174.9 g

Mass percent of solution = ?

Solution:

Mass of solution = 45.09 g + 174.9 g

Mass of solution = 220 g

The solute in 220 g is 45.09 g

220 g = 2.22 × 45.09

In 100 g solution amount of solute:

45.09 g/2.22 = 20.3 g

Thus m/m% = 20.3 % NaCl

5 0

4 years ago

Given the following information:

Katyanochek1 [597]

Step by Step Explanation

From the question,
the dimensions of the tank are;

L = 30 cm, way =0.075m and H = 15 cm

The density of water is given as
$D = 1g {cm}^{ - 3}$

The unit of density given in the question means that the mass of the water is in grams and the volume should also be in
${cm}^{3}$

To find the volume of the water, we first convert the units of dimensions given in inches and metres to centimetres

$1 inch = 2.54 cm$

This implies that ,

$H=15 inches=15×2.54cm=38.1cm$

Also,

$100cm=1m$

This implies that,
$w= \frac{0.075}{100 } = 7.5 \times {10}^{ - 4} cm$

Now, the volume of water in the tank can hold, can be found from the relation;

$V=L\times W\times H$

This implies that,

$v = 30cm \times (7.5 \times {10}^{ - 4} )cm \times 38.1cm$

$v = 0.857 {cm}^{3} \: to \: 3 \: d.p$

Finally, we can calculate the mass of the water from the relation given;

$D=\frac{M}{V}$

This in implies that

$1g {cm}^{ - 3} = \frac{m}{0.857 {cm}^{3} }$
$m = 1g {cm}^{ - 3} \times 0.857 {cm}^{3}$
$m = 0.857g$

Hence the fish tank can hold 0.857g water.

4 0

3 years ago

Read 2 more answers

Equal volumes of 1 molar hydrochloric acid (hcl) and 1 molar sodium hydroxide base (naoh) are mixed. after mixing, the solution

Mademuasel [1]

HCl is a strong acid therefore complete ionisation takes place
HCl ---> H⁺ + Cl⁻
1 mol of HCl dissociates to form 1 mol of H⁺
NaOH is a strong base therefore complete ionisation takes place
NaOH ---> Na⁺ + OH⁻
1 mol of NaOH dissociates to form 1 mol of OH⁻ ions
equal number of moles of HCl and NaOH will dissociate to give out an equal number of moles of H⁺ and OH⁻ ions.
H⁺ + OH⁻ --> H₂O
equal amount of H⁺ and OH⁻ together forms H₂O
since all the H⁺ and OH⁻ have now reacted to form water molecules the solution now becomes neutral as there are no excess H⁺ ions to make the solution acidic and no excess OH⁻ ions to make the solution basic.

Therefore the solution will be neutral.

7 0

4 years ago