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Anestetic [448]
3 years ago
10

500000 x 396 / sqrt of 72

Mathematics
2 answers:
dimulka [17.4K]3 years ago
6 0

Answer:

the answer of 500000x396 is 198,000,000

adell [148]3 years ago
4 0

Answer:

hey, will you tell (at symbol)MichiChan i cant go on pixelart? i keep getting an error 400 on it and i cant do anything. i dont want her to think im ignoring her...thanks

Step-by-step explanation:

:P

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Which is the graph of the following equation?
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Graph D is the answer to this question
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What is the greatest product you can make by multiplying two 2-digit numbers? Explain.
Anestetic [448]
9801
99 is the greatest 2 digit number so if you do 99x99 you will get 9801
5 0
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A rectangle initially has width 7 meters and length 10 meters and is expanding so that the area increases at a rate of 8 square
Tems11 [23]

Answer:

The length of rectangular is increasing at a rate 0.5714 meters per hour.

Step-by-step explanation:

We are given the following in the question:

Initial dimensions of rectangular box:

Length,l = 10 m

Width,w = 7 m

\dfrac{dA}{dt} = 8\text{ square meters per hour}\\\\\dfrac{dw}{dt} = 40\text{ centimeters per hour} =0.4\text{ meters per hour}

We have to find the rate of increase of length.

Area of rectangle =

A = l\times w

Differentiating we get,

\displaystyle\frac{dA}{dt} = \frac{dl}{dt}w + \frac{dw}{dt}l

Putting values, we get,

8 = \dfrac{dl}{dt}(7) + (0.4)(10)\\\\\dfrac{dl}{dt}(7) = 8 -4\\\\\dfrac{dl}{dt} \approx 0.5714

Thus, the length of rectangular is increasing at a rate 0.5714 meters per hour.

5 0
3 years ago
14 divided by 3/8 ? (The question mark is not part of the problem...neither is this..)
dmitriy555 [2]
3 divided by 8 is .375
14 divided by .375 is 37.3 repeating
and the fraction for that is 112/3

4 0
3 years ago
Read 2 more answers
Carlos tried to find a fraction equivalent to 2/3. Below is his work. Which
Sliva [168]

Answer:

He did not multiply 2/3 by a fraction equal to 1.

Step-by-step explanation:

For example he could have multiplied 2/3 by 4/4

= 2*4/3*4 = 8/12,

8 0
3 years ago
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