Write a polynomial function in it's factored form with zeros 5, -1, and 2

Mathematics

1 answer:

inna [77]3 years ago

7 0

Answer:

(x - 5)(x + 1)(x - 2) = 0

Step-by-step explanation:

If a polynomial function has roots a, b, and c, then it is (x - a)(x - b)(x - c).

The roots here are 5, 1, and 2, so the factors are

(x - 5)(x - (1))(x - 2)

The function is:

(x - 5)(x + 1)(x - 2) = 0

You might be interested in

Sierra left $4.50 as a tip for a waiter. This was 18% of the bill before the tip. How much was her total bill before the tip?

Ksivusya [100]

Jk I guess it was $25 dollars

8 0

3 years ago

Read 2 more answers

I need help, WILL GIVE BRAINLIEST IF RIGHT. i need it in percents

atroni [7]

Answer:

2.) 33.33%

3.) 50%

Step-by-step explanation:

There is only one 5 and only one 2. There are 6 sides. The fraction is 2/6, and as a percent it's 33.33%.

There are 3 even numbers and three odd numbers. The chance of getting an even then an odd would be 3/6, or 50%.

8 0

4 years ago

Pls solve this question

just olya [345]

Answer:

${( \sqrt{ {x}^{ - 3} }) }^{5} = ({( {x}^{ - 3}) }^{ \frac{1}{2} } ) ^{5} \\ \\ = {x}^{ - 3 \times \frac{1}{2} \times 5} = {x}^{ - \frac{15}{2} } = \frac{1}{ {x}^{ \frac{15}{2} } }$

<em><u>Or ;</u></em>

${( \sqrt{ {x}^{ - 3} } )}^{5} = {( \sqrt{ \frac{1}{ {x}^{3} }} })^{5} = ( { \frac{ \sqrt{1} }{ \sqrt{ {x}^{3} } } })^{5} \\ \\ = ( { \frac{1}{ \sqrt{x} \sqrt{ {x}^{2} } } })^{5} = ({ \frac{1}{ x\sqrt{x} }})^{5} \\ \\ = ( \frac{ {(1)}^{5} }{ {x}^{5} ( \sqrt{x} )^{5} } ) = \frac{1}{ {x}^{5} \times {x}^{ \frac{1}{2} \times 5 } } \\ \\ = \frac{1}{ {x}^{5} \times {x}^{ \frac{5}{2} } } = \frac{1}{ {x}^{5} \sqrt{ {x}^{5} } } \\ \\ = \frac{1}{ {x}^{5} \sqrt{ {x}^{4} {x}^{1} } } = \frac{1}{ {x}^{5} \sqrt{x} \sqrt{( { {x}^{2} })^{2} } } \\ \\ = \frac{1}{ {x}^{5} {x}^{2} \sqrt{x} } = \frac{1}{ {x}^{7} \sqrt{x} } = \frac{ \sqrt{x} }{ {x}^{8} }$