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Maksim231197 [3]
3 years ago
5

Help me plzzzzzzzzzzzzzzzzzz.

Mathematics
1 answer:
mario62 [17]3 years ago
4 0

Answer:

5 \sqrt[3]{10}  + 4 \sqrt[3]{10}

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water stations will be placed every 600 meters of a fifteen kilometer race. how many water stations will be needed?
Snezhnost [94]
1km=1000metres
15km=15000 metres 
15000/600=25
25-1=24 (minus the last one)

hope this helps :)
5 0
3 years ago
Read 2 more answers
How to solve 45 45 90 triangle given hypotenuse?
statuscvo [17]
From the Special Triangle Theorem, the hypotenuse is equal to the side lengtht times the Sqrt(2).
So hypotenuse H = xSqrt(2), x=H/Sqrt(2).
Using numbers, if H = 7, then x = 7/Sqrt(2) = 7Sqrt(2)/2 to rationalize it.
 
4 0
3 years ago
Write an equation of the perpendicular bisector of the segment with endpoints G 9,8       and H 3,2      .
Norma-Jean [14]

Answer:

y = -x + 11

Step-by-step explanation:

The equation of a straight line is is given by:

y = mx + b; where m is the slope and b is the y intercept

The equation of the line joining G(9, 8) and H(3, 2) is given as:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-8=\frac{2-8}{3-9}(x-9)\\\\y-8=x-9\\\\y=x-1

The perpendicular bisector of the line joining G(9, 8) and H(3, 2) is perpendicular to the line joining G(9, 8) and H(3, 2) and passes through the midpoint of line joining G(9, 8) and H(3, 2).

Let (x, y) be the midpoint of the line joining G(9, 8) and H(3, 2). Hence:

x = (9 + 3)/2 = 6

y = (8 + 2)/2 = 5

The midpoint = (6, 5)

Two lines are perpendicular if the product of their slopes is -1.

The line joining G(9, 8) and H(3, 2) has a slope of 1, hence, the slope of the perpendicular bisector would be -1.

This means that the perpendicular bisector has a slope of -1 and passes through (6, 5). Using:

y-y_1=m(x-x_1)\\\\y-5=-1(x-6)\\\\y-5=-x+6\\\\y=-x+11

The equation of the perpendicular bisector is y = -x + 11

8 0
3 years ago
Solve the algebraic expression below (2/5) (10) + 8
Andrews [41]

Answer: 12.

Step-by-step explanation:

4 0
2 years ago
If a transversal is perpendicular to one of two parallel lines, then it is perpendicular to the other one
ivanzaharov [21]
The right angle up at the number one and the unknown angle down at 2 are corresponding angles. corresponding angles are congruent. therefore angle down by two is a right angle and so the transversal is perpendicu lar to both lines
8 0
2 years ago
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