Question

PLEASE HELP !! When finding the margin of error for the mean of a normally distributed population from a sample, what is the critical probability, assuming a confidence level of 58%?
0.21
0.42
0.58
0.79

Answer 1

Answer:

D) 0.79

Step-by-step explanation:

First, find alpha.

$\alpha$ = 1 - (confidence level / 100)

$\alpha$ = 1 - $\frac{58}{100}$

$\alpha$ = 1 - 0.58

$\alpha$ = 0.42

Then, you can solve for the critical probability.

p* = 1 - $\frac{\alpha}{2}$

p* = 1 - $\frac{0.42}{2}$

p* = 1 - 0.21

p* = 0.79

Answer 2

Wouldn’t it be 0.58 because if you turn 58% into a decimal it will be 0.58.