DOES ANYONE TAKE FLVS CHEMISTRY? Please answer only if you do, thanks :)

podryga [215]

For the rectangle you add 12 plus 9 to get 21 then multiply by 24 to get 288. then. you multiply 15 times 9 to get 135 then divide by 2 to get 67.5 for the top triangle. you then add 12 and 9 together to get 21 and multiply that by 15 to find the middle rectangle then you get 315. you then add all of the final values together to get 670.5 square units

3 0

3 years ago

Terri Vogel, an amateur motorcycle racer, averages 129.71 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation o

Vikki [24]

Answer:

(a) The percent of her laps that are completed in less than 130 seconds is 55%.

(b) The fastest 3% of her laps are under 125.42 seconds.

(c) The middle 80% of her laps are from 126.80 seconds to 132.63 seconds.

Step-by-step explanation:

The random variable X is defined as the number of seconds for a randomly selected lap.

The random variable X is normally distributed with mean, μ = 129.71 seconds and standard deviation, σ = 2.28 seconds.

Thus, $X\sim N(129.71,\ 2.28^{2})$ .

(a)

Compute the probability that a lap is completes in less than 130 seconds as follows:

$P(X$

$=P(Z$

The percentage is, 0.55 × 100 = 55%.

Thus, the percent of her laps that are completed in less than 130 seconds is 55%.

(b)

Let x represents the 3rd percentile.

That is, P (X < x) = 0.03.

⇒ P (Z < z) = 0.03

The value of z for the above probability is:

z = -1.88

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\-1.88=\frac{x-129.71}{2.28}\\x=129.71-(1.88\times 2.28)\\x=125.4236\\x\approx 125.42$

Thus, the fastest 3% of her laps are under 125.42 seconds.

(c)

Let x₁ and x₂ be the values between which the middle 80% of the distribution lie.

That is,

$P(x_{1}$

The value of z for the above probability is:

z = 1.28

Compute the values of x₁ and x₂ as follows:

$-z=\frac{x_{1}-\mu}{\sigma}\\-1.28=\frac{x_{1}-129.71}{2.28}\\x_{1}=129.71-(1.28\times 2.28)\\x=126.7916\\x\approx 126.80$ $z=\frac{x_{2}-\mu}{\sigma}\\1.28=\frac{x_{2}-129.71}{2.28}\\x_{2}=129.71+(1.28\times 2.28)\\x=132.6284\\x\approx 132.63$

Thus, the middle 80% of her laps are from 126.80 seconds to 132.63 seconds.

5 0

3 years ago

Solve the equation. What is the value of x? x minus 6.8 = 356.3

koban [17]

Answer:

the answer is 363.1 i used a calculater to find the answer. so 356.3+ 6.8 = 363.1 so x=363.1

Step-by-step explanation:

3 0

3 years ago

I need help please I will give points and brainlest

Nastasia [14]

Answer:

a. 2 7/9 miles

b. 21.6 minutes

c. 8 1/3 miles

Step-by-step explanation:

The rate at which Catlin runs can be determined from the graph by finding the coordinates of a grid point that lies on the line. The line goes through the origin, so the relationship between time and distance is proportional.

We see that the point (miles, minutes) = (1 2/3, 12) lies on the graph, so the contant of proportionality is ...

k = y/x = 12/(5/3) = 36/5 = 7.2 . . . . minutes/mile

__

The proportion can be written ...

distance/(20 minutes) = (1 mile)/(7.2 minutes)

distance = (20/7.2) miles = 2 7/9 miles

Catlin will run 2 7/9 miles in 20 minutes

__

The proportion can be written ...

time/(3 miles) = (7.2 minutes)/(1 mile)

time = (3)(7.2 minutes) = 21.6 minutes

Catlin was running 21.6 minutes

__

In 1 hour, Catlin will run 3 times as far as in 20 minutes. Using the result from part A, we find ...

3(2 7/9 miles) = 8 1/3 miles 8 1/3 miles

Catlin will run 8 1/3 miles in one hour.

_____

Additional comment

Once we have a relationship between minutes and miles, we can write proportions with either of those numbers in the numerator or denominator. We find it convenient to put the unknown value in the numerator of a proportion, which is why the ratios are written differently in the different parts of the problem.

3 0

2 years ago

What are graphs used for? Select all that apply.

elena55 [62]

All of the above. Data is a thing that can be tracked no matter how much of it there is, so all apply.

5 0

3 years ago