An electron in the hydrogen atom makes a transition from an energy state of principal

The average time it takes to walk a mile is 0.33 hours. What is this time in seconds?

Lerok [7]

Answer: 19.8 seconds

Explanation:

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4 0

3 years ago

How many moles of carbon dioxide are produced when 5.12 moles of glucose undergoes a combustion reaction?

SVEN [57.7K]

Answer: 30.72 moles of $CO_2$ will be produced from 5.12 moles of glucose.

Explanation:

The balanced chemical equation for combustion of glucose is:

$C_6H_{12}O_6+6O_2\rightarrow 6CO_2+6H_2O$

According to stoichiometry :

1 moles of glucose produce = 6 moles of $CO_2$

Thus 5.12 moles of glucose produce = $\frac{6}{1}\times 5.12=30.72moles$ of $CO_2$

Thus 30.72 moles of $CO_2$ will be produced from 5.12 moles of glucose.

8 0

3 years ago

How is biotechnology useful for society?

FrozenT [24]

Answer:

It can create a new plant variety, cure diseases or like the current epidemic situation, vaccines, drugs, ...

Explanation:

5 0

3 years ago

Calculate the equilibrium concentration of H 3 O H3O in a 0.20 M M solution of oxalic acid. Express your answer to two significa

Black_prince [1.1K]

Answer: The equilibrium concentration of $H_3O^+$ ion is $8.3064\times 10^{-2}M$

Explanation:

We are given:

Molarity of oxalic acid solution = 0.20 M

Oxalic acid $(H_2C_2O_4)$ is a weak acid and will dissociate 2 hydrogen ions.

The chemical equation for the first dissociation of oxalic acid follows:

$H_2C_2O_4(aq.)+H_2O\rightleftharpoons H_3O^+(aq.)+HC_2O_4^-(aq.)$

Initial: 0.20

At eqllm: 0.20-x x x

The expression of first equilibrium constant equation follows:

$Ka_1=\frac{[H_3O^+][HC_2O_4^{-}]}{[H_2C_2O_4]}$

We know that:

$Ka_1\text{ for }H_2C_2O_4=0.059$

Putting values in above equation, we get:

$0.059=\frac{x\times x}{(0.20-x)}\\\\x=-0.142,0.083$

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of hydronium ion = x = 0.083 M

The chemical equation for the second dissociation of oxalic acid:

$HC_2O_4^-(aq.)+H_2O\rightarrow H_3O^+(aq.)+C_2O_4^{2-}(aq.)$

Initial: 0.083

At eqllm: 0.083-y 0.083+y y

The expression of second equilibrium constant equation follows:

$Ka_2=\frac{[H_3O^+][C_2O_4^{2-}]}{[HC_2O_4^-]}$

We know that:

$Ka_2\text{ for }H_2C_2O_4=6.4\times 10^{-5}$

Putting values in above equation, we get:

$6.4\times 10^{-5}=\frac{(0.083+y)\times y}{(0.083-y)}\\\\y=-0.083,0.0000639$

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of hydronium ion = y = 0.0000639 M

Total concentration of hydronium ion = [x + y] = [0.083 + 0.0000639] = 0.0830639 M

Hence, the equilibrium concentration of $H_3O^+$ ion is $8.3064\times 10^{-2}M$

7 0

3 years ago

Determine whether the following reaction is a Lewis acid/base reaction and if so, what is the Lewis acid: Fe3+(aq) + 6 CN−(aq) →

Aleonysh [2.5K]

Answer: It is a Lewis acid/base reaction, and $Fe^{3+}$ is the Lewis acid.

Explanation:

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

$Fe^{3+}$ can readily accept electrons and thus act as a lewis acid which is short of electrons.

$CN^-$ can readily lose electrons and thus act as a lewis base which has excess of electrons.

It is a Lewis acid/base reaction, and $Fe^{3+}$ is the Lewis acid.

4 0

4 years ago