90 < [( n + n + 2 + n + 4) / 2] < 105
90 < (3n + 6) / 2 < 105
3n + 6 > 180 and 3n + 6 < 210
n > 58 , n < 68
58 < n < 68 answer
It's 3/4 because (y2-y1)/(x2-x1)
Answer:
25% of 200 is 50
Step-by-step explanation
40% of a number is 80
.40 * n = 80
Divide each side by .4
.40 n/.4 = 80/.4
n = 200
The number is 200
Now lets find 25 percent of that number
.25 * 200 = 50
Complete Question
In a genetic experiment on peas, one sample of offspring contained 436 green peas and 171 yellow peas. Based on those results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of 3/4 that was expected? The probability of getting a green pea is approximately: Is the probability reasonably close to 3/4?
Answer:
The probability is 
Yes the result is reasonably close
Step-by-step explanation:
From the question we are told that
The number of of green peas is 
The number of yellow peas is 
The sample size is 
The probability of getting an offspring pea that is green is mathematically represented as



Comparing
to
we see that the result is reasonably close
The linear relationship which exists between the change in weight and number of days of hibernation in a hedgedog can be modeled using the equation y = - 0.03 + 0
- Change in weight per day of hibernation = - 0.03
- Change in weight for 115 days = - 3.45 ounces
A linear model can be created using the data in the table given using a regression calculator or excel ;
The linear model obtained in the form y = m + bx is :
- y = - 0.03x + 0
- y = change in weight
- x = number of days of hibernation
- Intercept = 0
- Slope = -0.03
- The slope value of the function gives the change in weight value per number of days of hibernation ; which is -0.03.
- Using the regression equation, substitute, the vlaue of x = 115
- -0.03(115) + 0 = - 3.45
Therefore, the change in weight after 115 days of hibernation is - 3.45 ounces.
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