Choice-D is the correct statement.
The electric potential at point b experienced by the charge cab be determined using the formulas given.
<h3>Electric potential</h3>
The electric potential of a point charge is the work done in moving the charge from infinity to certain point against the electric field.
V = Ed
V = (F/q)d
V = (Fd)/q
where;
- V is the electric potential
- F is electric force
- E is the electric field
- q is the charge
Thus, the electric potential at point b experienced by the charge cab be determined using the formulas given.
Learn more about electric potential here: brainly.com/question/14306881
Answer: the correct answer is 7.8026035971 x 10^(-13) joule
Explanation:
Use Energy Conservation. By ``alpha decay converts'', we mean that the parent particle turns into an alpha particle and daughter particles. Adding the mass of the alpha and daughter radon, we get
m = 4.00260 u + 222.01757 u = 226.02017 u .
The parent had a mass of 226.02540 u, so clearly some mass has gone somewhere. The amount of the missing mass is
Delta m = 226.02540 u - 226.02017 u = 0.00523 u ,
which is equivalent to an energy change of
Delta E = (0.00523 u)*(931.5MeV/1u)
Delta E = 4.87 MeV
Converting 4.87 MeV to Joules
1 joule [J] = 6241506363094 mega-electrón voltio [MeV]
4 mega-electrón voltio = 6.40870932 x 10^(-13) joule
4.87 mega-electrón voltio = 7.8026035971 x 10^(-13) joule
Answer:
R = 668.19 ft
Explanation:
given,
speed of the ball thrown by the pitcher = 100 mph
to travel maximum distance θ = 45°
distance traveled by the ball = ?
using formula
1 mph = 0.44704 m/s
100 mph = 44.704 m/s


R = 203.71 m
1 m = 3.28 ft
R = 203.71 × 3.28
R = 668.19 ft
hence, ball will go at a distance of 668.19 ft when pitcher throw it at 100 mph.