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guajiro [1.7K]
3 years ago
11

NEED HELP ASAP!!!

Physics
1 answer:
sineoko [7]3 years ago
5 0

Answer:

2,500 watts

Explanation:

I got this answer right on a test. I hope it works for you to.

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If the speed of a wave is 1500m/sec and its frequency is 200 Hz, what is its wavelength
Ray Of Light [21]

Answer:

The wavelength of wave is 7.5 meter.

Given:

Speed of wave = 1500 \frac{m}{s}

Frequency of wave = 200 Hz

To find:

Wavelength of wave = ?

Formula used:

\lambda = \frac{v}{n}

Where \lambda = wavelength of the wave

v = speed of wave

n = frequency of wave

Solution:

Wavelength of wave is given by,

\lambda = \frac{v}{n}

Where \lambda = wavelength of the wave

v = speed of wave

n = frequency of wave

\lambda = \frac{1500}{200}

\lambda = 7.5 m

The wavelength of wave is 7.5 meter.

4 0
3 years ago
Preston tossed a red ball upward and it reaches a maximum height of 3.0. What is the final velocity when it returns to prestons
Leokris [45]
That will depend on the units of the 3.0. We need to know if it's 3 feet, 3 yards, 3 meters, or 3 miles. Each one will have a different answer.
5 0
2 years ago
if the velocity of a car is halved the fc required to keeo it in a path of constant radius is multiplied/divided by?
damaskus [11]
I believe this is it
The centripetal force is given by
F = mv^2 / r
When v' = v/2,
F' = mv'^2/r = m(v/2)^2/r = mv^2/4r = F/4.
So the centripetal force is divided by 4.
7 0
3 years ago
Read 2 more answers
An electron in a television tube is accelerated uniformly from rest to a speed of 8.4\times 10^7~\text{m/s}8.4×10 ​7 ​​ m/s over
stich3 [128]

Answer:

P=3.42×10^-6 J/s

Explanation:

From the kinematics of motion with constant acceleration we know that :  

vf^2=vi^2+2*a(xf-xi)

Where :

• vf , vi, are the the final and the initial velocity of the electron  

• a is the acceleration of the electron  

• xf , xi are the final and the initial position of the electron .

Strategy for solving the problem : at first from the given information we calculate the acceleration of the electron.  

Givens: vf = 8.4 x 10^7 m/s , vi, = 0 m/s , xf = 0.025 m and xi = 0 m  

vf^2 =vi^2+2*a(xf-xi)

vf^2-vi^2=2*a(xf-xi)

2*a(xf-xi)= vf^2-vi^2

          a = (vf^2-vi^2)/2(xf-xi)

Pluging known information to get :

a = (vf^2-vi^2)/2(xf-xi)

  = 1.411 × 10^17

From the acceleration and the previous Eq. we can calculate the final velocity of the electron but a new position xf = 0.01 m  

so,

vf^2 =vi^2+2*a(xf-xi)

vf^2 =5.312× 10^7

From the following Eq. we can calculate the time elapsed in this motion .  

xf =xi+vi*t+1/2*a*t

xf =xi+vi*t+1/2*a*t

  t=√2(xf-xi)/a

 t=3.765×10^-10 s

now we can use the power P Eq.  

 P=W/Δt => ΔK/Δt  

Where: the work done W change the kinetic energy K of the electron ,

ΔK=Kf-Ki=>1/2*m*vf^2-1/2*m*vi^2

P=1/2*m*vf^2-1/2*m*vi^2/Δt

P=3.42×10^-6 J/s

6 0
3 years ago
6. A light ray strikes a reflective plane surface at an angle of 560 with the surface.
Zolol [24]

Answer:

deez nouts

Explanation:

5 0
2 years ago
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