Answer:
854.39 N
Explanation:
The formula for the fundamental frequency of a stretched string is given as,
f = 1/2L√(T/m)..................... Equation 1
Where f = fundamental frequency, L = Length of the wire, T = Tension, m = mass per unit length.
Given: f = 261.6 Hz, L = 0.6 m, m = (5.2×10⁻³/0.6) = 8.67×10⁻³ kg/m.
Substitute into equation 1
261.6 = 1/0.6√(T/8.67×10⁻³)
Making T the subject of the equation,
T = (261.6×0.6×2)²(8.67×10⁻³)
T =854.39 N
Hence the tension of the wire is 854.39 N.
When a toy truck collides into a toy car, the momentum of ____ is the same before and after the collision.
the truck plus the car
Answer:
a
Explanation:
<em>a_c</em><em> </em><em>=</em><em> </em><em>v</em><em>_t</em><em>^</em><em>2</em><em>/</em><em>r</em>
<em>a_c</em><em> </em><em>=</em><em> </em>(0.5)^2/0.03
<em>a_c</em><em> </em><em>=</em><em> </em>8.33 m/s^2