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Dmitry [639]
4 years ago
10

Which of the following is an example of work being done on an object?

Physics
2 answers:
slega [8]4 years ago
6 0

the answer is d. all of these

tensa zangetsu [6.8K]4 years ago
4 0

Answer:

d. All of these

Explanation:

work is said to be done when a force is applied to an object through a certain distance. the SI unit of workdone is joules or newton per meter

mathematically

workdone = force x distance.

from the answers,  work is being done because there is force applied in a certain distance.

  • from wagon is used to carry vegetables from a garden.
  • pulley is used to get water from a well.
  • hammer is used to remove a nail from a wall.

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The radius of the aorta is about 1 cm and the blood flowing through it has a speed of about 30 cm/s. Calculate the average speed
puteri [66]

Answer:

The average speed of the blood in the capillaries is 0.047 cm/s.

Explanation:

Given;

radius of the aorta, r₁ = 1 cm

speed of blood, v₁ = 30 cm/s

Area of the aorta, A₁ = πr₁² = π(1)² = 3.142 cm²

Area of the capillaries, A₂ = 2000 cm²

let the average speed of the blood in the capillaries = v₂

Apply continuity equation to determine the average speed of the blood in the capillaries.

A₁v₁ = A₂v₂

v₂ = (A₁v₁) / (A₂)

v₂ = (3.142 x 30) / (2000)

v₂ = 0.047 cm/s

Therefore, the average speed of the blood in the capillaries is 0.047 cm/s.

4 0
2 years ago
3. Compare the slope of the velocity-time graph to the average of all your acceleration values. Are they close? What does the sl
Marina86 [1]

The slope of a speed-time graph is the acceleration represented by the graph.

All other parts of this question refer to a lab experiment or exercise
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6 0
3 years ago
Whiteout friction you could not, write, drive or fly and airplane. Why not?
aleksklad [387]

friction is the resistance that one surface or object encounters when moving over another. Due to gravity pulling everything down things need to friction in order to move

i hope this helps :/


7 0
3 years ago
A ball is thrown vertically upwards with a velocity of 9.8 m/s. Its velocity after 1 second will be
Reil [10]

\LARGE{ \underline{\underline{ \purple{ \bf{Required \: answer:}}}}}

GiveN:

  • Initial velocity = 9.8 m/s²
  • Accleration due to gravity = -9.8 m/s²
  • Time taken = 1 s

To FinD:

  • Final velocity of the ball?

Step-by-step Explanation:

Using the first Equation of motion,

⇒ v = u + gt

⇒ v = 9.8 + -9.8(1)

⇒ v = 0 m/s

The final velocity is hence <u>0</u><u> </u><u>m</u><u>/</u><u>s</u><u>.</u>

<h3>Note:</h3>

  • While solving questions of under gravity motions using equations of motion, remember the sign convection to avoid mistakes.
  • You can consider positive above the ground and negative for towards it.
5 0
2 years ago
A hockey player hits a rubber puck from one side of the rink to the other. It has a mass of .170 kg, and is hit at an initial sp
Dimas [21]

By using third law of equation of motion, the final velocity V of the rubber puck is 8.5 m/s

Given that a hockey player hits a rubber puck from one side of the rink to the other. The parameters given are:

mass m =  0.170 kg

initial speed u = 6 m/s.

Distance covered s = 61 m

To calculate how fast the puck is moving when it hits the far wall means we are to calculate final speed V

To do this, let us first calculate the kinetic energy at which the ball move.

K.E = 1/2mU^{2}

K.E = 1/2 x 0.17 x 6^{2}

K.E = 3.06 J

The work done on the ball is equal to the kinetic energy. That is,

W = K.E

But work done = Force x distance

F x S = K.E

F x 61 = 3.06

F = 3.06/61

F = 0.05 N

From here, we can calculate the acceleration of the ball from Newton second law

F = ma

0.05 = 0.17a

a = 0.05/0.17

a = 0.3 m/s^{2}

To calculate the final velocity, let us use third equation of motion.

V^{2} = U^{2} + 2as

V^{2}  = 6^{2} + 2 x 0.3 x 61

V^{2} = 36 + 36

V^{2} = 72

V = \sqrt{72}

V = 8.485 m/s

Therefore, the puck is moving at the rate of 8.5 m/s (approximately) when it hits the far wall.

Learn more about dynamics here: brainly.com/question/402617

5 0
2 years ago
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