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3 years ago

11

What is a primary source?

1 answer:

Fed [463]3 years ago

6 0

//////Correct answer is C.///////

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Represent the following sentence as an algebraic expression, where "a number" is the

agasfer [191]

Answer:

2 (x+3)

Explanation:

8 0

3 years ago

Red light has a wavelength of 500 nm. What is the frequency of red light?

snow_tiger [21]

Answer:

$0.6 \times 10 {}^{15}$

Explanation:

By using relation,

Speed of light = frequency × wavelength (in m)

3 0

3 years ago

a 1.5 kg ball is thrown vertically upward with an initial speed of 15 m/s. if the initial potential energy is taken as zero, fin

trapecia [35]

Answer:

a) $E_{p} = 0$

$E_{k} = 168.7 J$

$E_{m} = 168.7 J$

b) $E_{p} = 73.6 J$

$E_{k} = 95.8 J$

$E_{m} = 169.4 J$

c) $E_{p} = 169.2 J$

$E_{k} = 0$

$E_{m} = 169.2 J$

Explanation:

We have:

m: is the ball's mass = 1.5 kg

v₀: is the initial speed = 15 m/s

g: is the gravity acceleration = 9.81 m/s²

a) In the initial position we have:

h: is the height = 0

The potential energy is given by:

$E_{p} = mgh = 0$

The kinetic energy is:

$E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(15)^{2} = 168.7 J$

And the mechanical energies:

$E_{m} = E_{p} + E_{k} = 0 + 168.7 J = 168.7 J$

b) At 5 m above the initial position we have:

h = 5 m

The potential energy is:

$E_{p} = mgh = 1.5*9.81*5 = 73.6 J$

Now, to find the kinetic energy we need to calculate the speed at 5 m:

$v_{f}^{2} = v_{0}^{2} - 2gh = (15)^{2} - 2*9.81*5 = 126.9$

$v_{f} = \sqrt{126.9} = 11.3 m/s$

$E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(11.3)^{2} = 95.8 J$

And the mechanical energies:

$E_{m} = E_{p} + E_{k} = 73.6 + 95.8 J = 169.4 J$

c) At its maximum height:

$v_{f}$ : is the final speed = 0

$h = \frac{v_{0}^{2}}{2g} = \frac{(15)^{2}}{2*9.81} = 11.5 m$

Now, the potential, kinetic and mechanical energies are:

$E_{p} = mgh = 1.5*9.81*11.5 = 169.2 J$

$E_{k} = \frac{1}{2}mv^{2} = 0$

$E_{m} = 169.2 J + 0 = 169.2 J$

I hope it helps you!

7 0

3 years ago

Which of the following sequences describes the path by which electrons travel downhill energetically in aerobic respiration

Vlad1618 [11]

Answer:

glucose → NADH → electron transport chain → oxygen.

Explanation:

Aerobic respiration is also called as cellular respiration, in which electrons are picked up by the FADH, and NADH from the food. Then through a proton pump electrons are transferred to the electron transport chain, in this, the activity of the proton pump generates an electrochemical gradient, then this gradient used by the ATP synthase enzyme to produce ATP.

In aerobic respiration, the last acceptor of electron is oxygen. An electron is donated to oxygen for the formation of the water.

5 0

4 years ago

Research on the Big Five has indicated that approximately _____ percent of traits appear to be inherited.

Evgen [1.6K]

D 50
Hopefully this helps!

4 0

3 years ago

Read 2 more answers