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dezoksy [38]
3 years ago
5

A student wants to get real and inverted

Physics
1 answer:
sveta [45]3 years ago
5 0

Answer:

concave mirror

Explanation:

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1. How would you expect an instantaneous acceleration vs. time graph to look for a cart moving with a constant
r-ruslan [8.4K]

Answer:

a=0   v = v₀ + a t

a=0    line is horizontal

Explanation:

1, In a graph of acceleration vs. time, we have lines, when the line is horizontal it is zero, when the line has a positive slope the increasing accelerations and when the slope is negative the decreasing acceleration

2, speed and relationship of a car is given by

        v = v₀ + a t

where vo is the initial velocity, a is the acceleration and tel time

in this case I will calcograph velocity vs. time the constant acceleration is a straight line.

In general from the graph we can find the initial velocity with the cut at that x and the acceleration of the car with the slope

6 0
3 years ago
A baseball hits a car, breaking its window and triggering its alarm which sounds at a frequency of 1210 Hz. What frequency (in H
IRINA_888 [86]

Answer:

The frequency of sound heard by the boy is 1181 Hz.

Explanation:

Given that,

Frequency of sound from alarm  f_{0} = 1210\ Hz

Speed = -8.25 m/s

Negative sign show the boy riding away from the car

Speed of sound = 343

We need to calculate the heard frequency

Using formula of frequency

f = f_{0}(\dfrac{v+v_{0}}{v-v_{s}})

Where, f_{0} = frequency of source

v_{0} = speed of observer

v_{s} = speed of source

v = speed of sound

Put the value into the formula

f=1210\times\dfrac{343+(-8.25)}{343-0}

here, source is at rest

f=1180.8\ Hz

f=1181\ Hz

Hence, The frequency of sound heard by the boy is 1181 Hz.

8 0
3 years ago
The mass of the bicycle and rider is 60 kg and the total area of the tyres in contact with
AleksAgata [21]

Answer:

a little

Explanation:

First of all, it's not how you spell "tyres", it is tires.

Second of all, you already know the Mass so what you need to find out now is  contact the road. You Know that your number and letter are squared so that would turn into 6m x 2.4. Then you do the math do continue on to finish it. Have a great day!! Good luck with the answer!!

3 0
3 years ago
A dog, that has a mass of 16 kgs, runs across a yard. What is the average force applied to the dog from the ground as it runs ac
VikaD [51]

Answer:

156.96 N

Explanation:

F=ma where m is the mass and a is acceleration

Substituting 16 Kg for m and 9.81 m/s2 for g then

F=16*9.81= 156.96 N

4 0
3 years ago
a grape and apple and a watermelon are arranged at the corners of a triangle so that each piece of fruit is three meters away fr
777dan777 [17]
-- There are three pairs of mass with gravitational forces between them.

-- The distances between the masses are the same for each pair.

-- The only other quantity that determines the strength of the gravitational
force is the product of the masses.

-- The product of the masses is greatest for the apple and the watermelon,
so the strength of the gravitational force between them is the greatest.
5 0
2 years ago
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