Answer:
a.proton, proton
hope this helped :) have a goodday
Answer:
FORCE - rate of change of momentum, ie its changing velocity [change in velocity is of more concern] NEWTON
WORK - product of force and displacement, ie [velocity may be constant or variable but change in position with certain force is of more concern] JOULES
I hope you understood from this..
Complete question:
if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.
Answer:
The mutual force between the two point charges is 319.64 N
Explanation:
Given;
distance between the two point charges, r = 1.5 cm = 1.5 x 10⁻² m
value of the charges, q₁ and q₂ = 2 μC and - μ4 C
Apply Coulomb's law;

where;
F is the force of attraction between the two charges
|q₁| and |q₂| are the magnitude of the two charges
r is the distance between the two charges
k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

Therefore, the mutual force between the two point charges is 319.64 N
Many ways, but some of the most famous are kicks (side, back, front, snap) or a smash.
Hope it helped! :)
Answer:
I hope it's helpful for you ☺️