Answer:
22 N upward
Explanation:
From the question,
Applying newton's second law of motion
F = m(v-u)/t....................... Equation 1
Where F = Average force exerted by the ground on the ball, m = mass of the baseball, v = final velocity, u = initial velocity, t = time of contact
Note: Let upward be negative and downward be positive
Given: m = 0.14 kg, v = -1.00 m/s, u = 1.2 m/s, t = 0.014 s
Substitute into equation 1
F = 0.14(-1-1.2)/0.014
F = 0.14(-2.2)/0.014
F = 10(-2.2)
F = -22 N
Note the negative sign shows that the force act upward
convection
please mark brainliest any other problems or questions feel free to ask
In solids, particles or atom are very closely arranged compared to gasses. When these particles are arranged in such proximity, vibrations from sound are very easily transmitted from one particle to another in the solid. Hence, the sound vibrations can travel through the solid medium more quickly than through a gas medium.
Speed of sound also depends on its frequency and the wavelength.
Answer:
![\omega_f = 3.584\ rad/s](https://tex.z-dn.net/?f=%5Comega_f%20%3D%203.584%5C%20rad%2Fs)
Explanation:
given,
turntable rotate to, θ = 5 rad
time, t = 2.8 s
initial angular speed = 0 rad/s
final angular speed = ?
now, using equation of rotational motion
![\theta = \omega_i t + \dfrac{1}{2}\alpha t^2](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Comega_i%20t%20%2B%20%5Cdfrac%7B1%7D%7B2%7D%5Calpha%20t%5E2)
![5 = 0+ \dfrac{1}{2}\alpha\times 2.8^2](https://tex.z-dn.net/?f=5%20%3D%200%2B%20%5Cdfrac%7B1%7D%7B2%7D%5Calpha%5Ctimes%202.8%5E2)
![\alpha= \dfrac{10}{2.8^2}](https://tex.z-dn.net/?f=%5Calpha%3D%20%5Cdfrac%7B10%7D%7B2.8%5E2%7D)
α = 1.28 rad/s²
now, calculation of angular velocity
![\omega_f = \omega_i + \alpha t](https://tex.z-dn.net/?f=%5Comega_f%20%3D%20%5Comega_i%20%2B%20%5Calpha%20t)
![\omega_f =0 +1.28\times 2.8](https://tex.z-dn.net/?f=%5Comega_f%20%3D0%20%2B1.28%5Ctimes%202.8)
![\omega_f = 3.584\ rad/s](https://tex.z-dn.net/?f=%5Comega_f%20%3D%203.584%5C%20rad%2Fs)
hence, the angular velocity at the end is equal to 3.584 rad/s
Answer:
a) v = √(v₀² + 2g h), b) Δt = 2 v₀ / g
Explanation:
For this exercise we will use the mathematical expressions, where the directional towards at is considered positive.
The velocity of each ball is
ball 1. thrown upwards vo is positive
v² = v₀² - 2 g (y-y₀)
in this case the height y is zero and the height i = h
v = √(v₀² + 2g h)
ball 2 thrown down, in this case vo is negative
v = √(v₀² + 2g h)
The times to get to the ground
ball 1
v = v₀ - g t₁
t₁ =
ball 2
v = -v₀ - g t₂
t₂ = - \frac{v_{o} + v }{ g}
From the previous part, we saw that the speeds of the two balls are the same when reaching the ground, so the time difference is
Δt = t₂ -t₁
Δt =
Δt = 2 v₀ / g