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lara31 [8.8K]
3 years ago
12

A diesel engine lifts the 225 kg hammer of a pile driver 20 m in 5 seconds. How much work is done on

Physics
1 answer:
ladessa [460]3 years ago
5 0

Answer:

a. Workdone = 44100 Joules

b. Power = 8820 Watts.

Explanation:

Given the following data:

Mass = 225kg

Distance = 20m

Time = 5 seconds

To find the workdone;

Workdone = force * distance

But force = mg

We know that acceleration due to gravity is equal to 9.8m/s²

Force = 225*9.8 = 2205N

Substituting the values into the equation, we have;

Workdone = 2205 * 20

Workdone = 44100 Joules

b. To find the power;

Power = workdone/time

Power = 44100/5

Power = 8820 Watts.

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Answer:300

Explanation:

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4 years ago
If a wave’s frequency is 16Hz and it’s wavelength is 10m. What’s the waves speed?
Vesna [10]

Answer:

160J

Explanation:

Given parameters:

Frequency  = 16Hz

Wavelength = 10m

Unknown:

Waves speed  = ?

Solution:

Waves speed is the product of frequency and wavelength;

  Waves speed  = fλ

f is the frequency

λ is the wavelength

Now insert the parameters and solve;

     Waves speed = 16 x 10  = 160J

4 0
3 years ago
A 149 turn 149 turn circular coil of radius 2.15 cm 2.15 cm is immersed in a uniform magnetic field that is perpendicular to the
adoni [48]

Answer:

Explanation:

number of turns, N = 149

radius, r = 2.15 cm

Area, A = πr² = 3.14 x 2.15 x 2.15 x 10^-4 = 1.45 x 10^-3 m^2

Change in magnetic field, ΔB = 95.5 - 50.5 = 45 mT = 45 x 10^-3 T

time, Δt = 0.165 second

induced emf

e = N x dФ/dt

where, dФ be the change in flux.

e = N x A x ΔB/Δt

e = 149 x 1.45 x 10^-3 x 45 x 10^-3 / 0.165

e = 0.058 V

4 0
3 years ago
A woman in a sprint race accelerates from rest to 8.7 m/s in 2.7 s. What is her displacement?​
Trava [24]

Answer:

23.49m

Explanation:

Distance =  velocity x time

8.7 x 2.7 = 23.49m

8 0
3 years ago
A helium balloon is filled to a volume of 2.88 x 103 L at 722 mm Hg and 19°C. When the balloon is released, it rises to an alti
inn [45]

Answer:

V₂=4.57 x 10³ L

Explanation:

Given that

V₁= 2.88 x 10³ L

P₁=722 mm  Hg

T₁ = 19°C

T₁ =292 K

P₂=339 mm Hg

T₂= - 55°C

T₂=218 K

Lets take final volume = V₂

We know that ideal gas equation

PV = m R T

By applying mass conservation

\dfrac{P_1V_1}{RT_1}=\dfrac{P_2V_2}{RT_2}

\dfrac{722\times 2.88\times 10^3}{292}=\dfrac{339\times V_2}{218}

V₂=4.57 x 10³ L

Therefore volume will be 4.57 x 10³ L

3 0
3 years ago
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