Answer:
3
Explanation:
the answer is number three
Answer: (1) centripetal force is inversely proportional to the radius of an object moving in a circular form.
Centripetal force = mv^{2}/r.
m=mass, v=velocity, r=radius.
(2). Doubling the mass affect the centripetal force following the fact that the centripetal force is directly proportional to the mass therefore, if the centripetal force increases four times (Radius kept constant), the mass increases two times.
(3) If radius is increased, then the centripetal force will decrease.
(4). If mass is doubled, then the centripetal force will also double.
Explanation:
from the above relation, centripetal force is inversely proportional to the radius and is directly proportional to the mass and velocity.
If only the centripetal force is increase and others are kept as it is, then the moving object will gradually move towards the focus point reducing the radius proportional to the increase in centripetal force.
for example:- relating to mass and velocity, if the centripetal force is increase four times, the mass or velocity will increase two times keeping the radius constant for the condition.
Answer:
31.2m/s
Explanation:
final velocity = initial velocity + acceleration • time
final velocity = 0 m/s + 6.58m/s/s • 4.74 s
final velocity = 31.2 m/s
Answer:
Newton first law states that a body at rest remains at rest or if it is motion, remains in motion at a constant unless acted upon by a external force
From Newton's Three Laws of Motion, derived formulas are already conveniently presented for a rectilinear motion at constant acceleration. One of its equations is
y = (Vf² - Vi²)/2a, where
y is the vertical height travelled by the object
Vf is the final velocity
Vi is the initial velocity
a is the acceleration
Now, when a man jumps, the only force acting on him is gravity pulling him down. When he reaches his maximum height, eventually his velocity will reach zero. So, Vf = 0. Suppose all parameters with subscript 1 refers to man jumping on Earth and those with subscript 2 refers to the man jumping on moon. Since initial velocity and angle is said to be the same, when we find the ratio of x₂/x₁, the terms (Vf²-Vi²) cancels out leaving us with
x₂/x₁ = a₂/a₁
It is common knowledge that gravity on Earth is 9.81 m/s². According to literature, the gravity on the moon is 1.62 m/s². Thus,
x₂/x₁ = a₁/a₂ = 9.81/1.62 = 6
x₂ = 6x₁
Therefore, the man jumping on the moon can reach 6 times higher than in Earth.
