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kogti [31]
3 years ago
10

Pls, help!!!

Mathematics
2 answers:
Yuliya22 [10]3 years ago
7 0
Hello!
First, 5 to 4.3 feet, to make it a bit easier, let’s multiply by 2, now we have 10 and 8.6. Since 8.6 - 10 = -1.4, the river dropped 14% in 1846-1847.
Second, we will find the change from 4.3 to 6, and 6 - 4.3 = 1.7, but we need to multiply it by 1.66…7, which approximately equals a 28.32% gain. Hope this helped ☺️
mestny [16]3 years ago
3 0
28.32%, that would be the answer
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Which is the standard form for this number?
netineya [11]

Step-by-step explanation:

To make it easy to read very large and small numbers, we write them in standard form. Any number that we can write as a decimal number, between 1.0 and 10.0, multiplied by a power of 10, is said to be in standard form. 1.98 ✕ 10¹³; 0.76 ✕ 10¹³ are examples of numbers in standard form.

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3 years ago
Which statement is true about the songs played during the<br> one-hour interval?
Nataliya [291]

Answer:

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3 years ago
A quadrilateral has vertices at A(–5, 5), B(1, 8), C(4, 2), D(–2, –2). Use slope to determine if the quadrilateral is a rectangl
lianna [129]

With the properties of rectangle in mind we must perform two verification. Verify to see if opposite sides are parallel and adjacent sides are perpendicular.

We need to determine the slope of each side, using the formula,

m=\frac{y_2-y_1}{x_2-x_1 }

<u>Slope  of AB</u>

m_{AB}=\frac{8-5}{1--5}

\Rightarrow m_{AB}=\frac{8-5}{1+5}

\Rightarrow m_{AB}=\frac{3}{6}

\Rightarrow m_{AB}=\frac{1}{2}


<u>Slope of BC</u>

m_{BC}=\frac{2-8}{4-1}

\Rightarrow m_{BC}=\frac{-6}{3}

\Rightarrow m_{BC}=-2

<u>Slope of CD</u>

m_{CD}=\frac{-2-2}{-2-4}

\Rightarrow m_{CD}=\frac{-2-2}{-2-4}

\Rightarrow m_{CD}=\frac{-4}{-6}

\Rightarrow m_{CD}=\frac{2}{3}

<u>Slope of AD</u>

m_{AD}=\frac{-2-5}{-2--5}

\Rightarrow m_{AD}=\frac{-2-5}{-2+5}

\Rightarrow m_{AD}=\frac{-7}{3}

<u>Verify Parallel sides</u>

If the quadrilateral is a rectangle, then opposite sides should have the same slope. But

m_{AD} = \frac{-7}{3} \neq m_{BC}=-2

m_{AB}=\frac{1}{2} \neq m_{CD}=\frac{2}{3}


<u>Verify Perpendicularity</u>

And also the product of slopes of all sides with a common vertex should be -1. But

m_{AB} \times m_{BC}=\frac{1}{2} \times -2=-1

m_{AB} \times m_{AD}=\frac{1}{2} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{AD}=\frac{2}{3} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{BC}=\frac{2}{3} \times -2 \neq -1


Since the quadrilateral fails to satisfy all these conditions, the quadrilateral is not a rectangle




6 0
3 years ago
Which choice correctly shows the solution(s) of the equation x2 = 121?
kvasek [131]

Hello from MrBillDoesMath!

Answer:

Choice D, x = +\ sqrt(121)


Discussion:

x^2 = 121           =>          take square roots of both sides

x = +\- sqrt(121) =>         as sqrt(121) = +\- 11

x = +\- 11                    

The closest answer is D as it includes both values of x,  unlike choices A and B which include a single value of the square root


Thank you,

MrB

7 0
4 years ago
On a coordinate plane, points (2, 4), (4, 8), and (5, 10) are plotted.
mario62 [17]

Step-by-step explanation:

(2, 4), (4, 8) and (5, 10) are on the line y = 2x.

Hence they line on a straight line,

The line passes through the origin, and

it shows a proportional relationship.

4 0
3 years ago
Read 2 more answers
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