What is the mass in grams of 2.25 mol of the element iron, Fe?
1 answer:
<h3>Answer:</h3>
126 g Fe
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<u>Step 1: Define</u>
2.25 mol Fe
<u>Step 2: Identify Conversions</u>
Molar Mass of Fe - 55.85 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
125.663 g Fe ≈ 126 g Fe
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Answer : The moles of left in the products are 0.16 moles.
Explanation :
First we have to calculate the moles of .
Using ideal gas equation:
where,
P = pressure of gas = 1 atm
V = volume of gas = 10 L
T = temperature of gas =
n = number of moles of gas = ?
R = gas constant = 0.0821 L.atm/mol.K
Now put all the given values in the ideal gas equation, we get:
Now we have to calculate the moles of .
The balanced chemical reaction will be:
From the balanced reaction we conclude that,
As, 1 mole of react with 2 moles of
So, 0.406 mole of react with
moles of
Now we have to calculate the excess moles of .
is 20 % excess. That means,
Excess moles of =
× Required moles of
Excess moles of = 1.2 × Required moles of
Excess moles of = 1.2 × 0.812 = 0.97 mole
Now we have to calculate the moles of left in the products.
Moles of left in the products = Excess moles of
- Required moles of
Moles of left in the products = 0.97 - 0.812 = 0.16 mole
Therefore, the moles of left in the products are 0.16 moles.