Pick the correct word to fill up the blank in below question: velocity, combustion, acceleration, gravitation, force

A child walks due east on the deck of a ship at 2 miles per hour. the ship is moving north at a speed of 18 miles per hour. find

garik1379 [7]

Refer to the figure shown below.

The velocity of the child and the velocity of the ship should be added vectorially to find the speed and direction of the child relative to the water surface.

The magnitude of the child's velocity is
v = √(2² + 18²) = 18.11 mph

The direction of the child's speed is
θ = tan⁻¹ (18/2) = tan⁻¹ 9 = 83.7° north of east or counterclockwise from the eastern direction.

Answer:
The magnitude is 18.1 mph.
The direction is 84° north of east.

8 0

3 years ago

A plane travels 27,000 meters in 90 seconds. What was its speed?

trapecia [35]

The plane goes 300mph

3 0

4 years ago

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Earth attracts a person with a gravitational force of 7.0 × 102 newtons. What is the magnitude of the force with which the indiv

kirza4 [7]

B. In the system of the object and the earth, by Newton's third law, the object will exert and equal and opposite force upon the earth.

3 0

4 years ago

Read 2 more answers

A lightning bolt transfers 6.0 coulombs of charge from a cloud to the ground. In 2.0*10^-3 second. What is the average current d

Savatey [412]

Answer:

sup cuh, i just want the point lol

Explanation: sorry not sorry reases

6 0

2 years ago

A particle with charge q and momentum p, initially moving along the x-axis, enters a region where a uniform magnetic field* B=(B

VMariaS [17]

Answer:

Magnitude of momentum = q × B0 × [d^2 + 2L^2] / 2d.

Explanation:

So, from the question, we are given that the charge = q, the momentum = p.

=> From the question We are also given that, "initially, there is movement along the x-axis which then enters a region where a uniform magnetic field* B = (B0)(k) which then extends over a width x = L, the distance = d in the +y direction as it traverses the field."

Momentum,P = mass × Velocity, v -----(1).

We know that for a free particle the magnetic field is equal to the centrepetal force. Thus, we have the magnetic field = mass,.m × (velocity,v)^2 / radius, r.

Radius,r = P × v / B0 -----------------------------(2).

Centrepetal force = q × B0 × v. ----------(3).

(If X = L and distance = d)Therefore, the radius after solving binomially, radius = (d^2 + 2 L^2) / 2d.

Equating Equation (2) and (3) gives;

P = B0 × q × r.

Hence, the Magnitude of momentum = q × B0 × [d^2 + 2L^2] / 2d.

4 0

3 years ago