Pick the correct word to fill up the blank in below question: velocity, combustion, acceleration, gravitation, force

Water enters a 2 m3 tank at a rate of 6 kg/s and is withdrawn at a rate of 2 kg/s. The tank is initially half full. What type of

NemiM [27]

Answer:

This process is semicontinuous.

Explanation:

Given that,

Volume = 2 m³

Enter flow rate = 6 kg/s

Exit flow rate = 2 kg/s

The tank is initially half full.

We need to find what type of process

Using given data,

This process is not continuous because given enter and exit flow rate is not equal.

This process is semicontinuous and the water level in the tank does not reach a constant level.

Hence, This process is semicontinuous.

8 0

3 years ago

Simpson drives his car with an average velocity of 48.0 km/h to the east. How long will it take him to drive 144 km on a straigh

Lorico [155]

Answer:

The time save by Simpson is 25.8 minutes.

Explanation:

Given that,

Velocity of the car, v = 48 km/h

Distance covered by the car, d = 144 km

Let t is the time taken by the car. Speed of an object is given by distance covered per unit time. It is given by :

$v=\dfrac{d}{t}$

$t=\dfrac{d}{v}$

$t=\dfrac{144\ km}{48\ km/h}$

t = 3 hours

If the velocity is increased to 56 km/h to the east. Time taken is given by :

$t'=\dfrac{144\ km}{56\ km/h}$

t' = 2.57 seconds

The time save by Simpson increasing his average velocity is given by :

$\Delta t=t-t'$

$\Delta t=3-2.57$

$\Delta t=0.43\ hours$

or

$\Delta t=25.8\ min$

So, the time save by Simpson is 25.8 minutes. Hence, this is the required solution.

5 0

4 years ago

The Palo Duro Canyon in the High Plains was originally formed by a fork in the Red River. The canyon continues to widen and deep

Dima020 [189]

Answer:

The correct answer for this Question is B

Explanation:

WIND AND WATER EROSION (B)

8 0

3 years ago

Read 2 more answers

A football is thrown horizontally with an initial velocity of(16.6 {\rm m/s} ){\hat x}. Ignoring air resistance, the average acc

Ray Of Light [21]

Answer:

A) 16.6 m/s i -17.2 m/s j B) 23.9 m/s c) 46º below horizontal.

Explanation:

A) Once released, the football is not under the influence of any external force in the horizontal direction, so it continues moving at a constant speed equal to the initial velocity, i.e., 16.6 m/s.

If we choose the horizontal direction to be coincident with the x-axis, and make positive the direction towards the right (assuming that this was the direction along which the football was thrown), we can write the horizontal component of the veelocity vector, as follows:

vₓ = 16.6 m/s i

In the vertical direction, the football, once released, is in free fall, starting from rest.

So, we can find the vertical component of the velocity vector, at a given point in time, applying the definition of acceleration, as follows:

vy = a*t = -g*t = -9.81 m/s²*1.75 s = -17.2 m/s

Assuming that the upward direction is the positive for the y-axis (perpendicular to the chosen x-axis), we can write the vertical component of the velocity vector, at t=1.75 s, as follows:

vy = -17.2 m/s j

So, the velocity vector, in terms of the unit vectors i and j, can be written in this way:

v = 16.6 m/s i -17.2 m/s j

b) The magnitude of this vector can be found applying trigonometry, as the magnitude is the hypotenuse of a triangle with sides equal to vx and vy, as follows:

$v =\sqrt{(16.6m/s)^{2}+ (-17.2m/s)^{2}} = 23.9 m/s$