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sattari [20]
3 years ago
10

Terminal velocity is usually defined as the

Physics
2 answers:
adoni [48]3 years ago
6 0
Using the word "Terminal" which means end, we can conclude that, in a nutshell, terminal velocity is when an object reaches a speed where it cannot go any faster. For example, if you jumped of the Empire State building, before you went "KURSPAT!" on the pavement below, you would enter Terminal Velocity. Your fall off the Empire State building would also be "terminal". eh? Hahahaha never try a physics joke.
Andre45 [30]3 years ago
4 0
The consent speed of something freely falling object eventually reaches the resistance of the medium through which it is falling prevents further acceleration. 
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A. Solid turns into a gas
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Why air pollution is a problem?
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8 0
3 years ago
PLEASE HELP ME IF YOU KNOW STUFF ABOUT ENERGY TYSM
Tomtit [17]

Answer:

  1. Kinetic Energy
  2. Potential energy
5 0
3 years ago
Read 2 more answers
An important dimensionless parameter in certain types of fluid flow problems is the Froude number defined as V/√g.l where V is a
prohojiy [21]

Answer:

1.24611

Explanation:

V = Velocity = 10 ft/s

L = Length = 2 ft

g = Acceleration due to gravity = 32.2 ft/s²

Froude number is given by

Fr=\dfrac{V}{\sqrt{gL}}\\\Rightarrow Fr=\dfrac{10}{\sqrt{32.2\times 2}}\\\Rightarrow Fr=1.24611

Converting to SI units

10\ ft/s=10\times \dfrac{1}{3.281}

32.2\ ft/s^2=32.2\times \dfrac{1}{3.281}

2\ ft=2\times \dfrac{1}{3.281}

Fr=\dfrac{V}{\sqrt{gL}}\\\Rightarrow Fr=\dfrac{10\times \dfrac{1}{3.281}}{\sqrt{32.2\times \dfrac{1}{3.281}\times 2\times \dfrac{1}{3.281}}}\\\Rightarrow Fr=1.24611

The Froude number is 1.24611

The Froude number is equal. The Froude number is dimensionless as the units cancel each other. In order for this to happen the units used need to be consitent either imperial or SI.

7 0
3 years ago
When 1,250^3/4 is written in simplest radical form, which value remains under the radical?
GaryK [48]

Answer:

125\sqrt[4]{8}

Explanation:

A number of the form

a^{\frac{m}{n}}

can be re-written in the radical form as follows:

\sqrt[n]{a^m}

In this problem, we have:

a = 1,250

m = 3

n = 4

So, if we apply the formula, we get

1,250^{\frac{3}{4}}=\sqrt[4]{(1,250)^3}

Then, we can rewrite 1250 as

1250 = 2\cdot 5^4

So we can rewrite the expression as

=\sqrt[4]{(2\cdot 5^4)^3}=5^3 \sqrt[4]{2^3}=125\sqrt[4]{8}

7 0
3 years ago
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