It protects the electrical appliance and the person from electrical shocks/faults.
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Answer:
2.2 meters
Explanation:
Potential energy, PE created by a charge, q at a radius r from the charge source, Q, is expressed as:

is Coulomb's constant.
#The electric field,
at radius r is expressed as:

From i and ii, we have:


#Substitute actual values in our equation:

Hence, the distance between the charge and the source of the electric field is 2.2 meters
Answer:
it's ii) R is correct while A is incorrect
Explanation:
cuz, both statements are correct but the reason is not the correct reason for the assertion,
Answer:
The kinetic energy of the proton at the end of the motion is 1.425 x 10⁻¹⁶ J.
Explanation:
Given;
initial velocity of proton,
= 3 x 10⁵ m/s
distance moved by the proton, d = 3.5 m
electric field strength, E = 120 N/C
The kinetic energy of the proton at the end of the motion is calculated as follows.
Consider work-energy theorem;
W = ΔK.E

where;
K.Ef is the final kinetic energy
W is work done in moving the proton = F x d = (EQ) x d = EQd




Therefore, the kinetic energy of the proton at the end of the motion is 1.425 x 10⁻¹⁶ J.
Answer:





Explanation:
To calculate average velocity we need the position for both instants t0 and t1.
Now we will proceed to calculate all the positions we need:





Replacing these values into the formula for average velocity:




To know the actual velocity, we derive the position and we get:
