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3 years ago

Which is one property of silt soils?

Physics

1 answer:

bekas [8.4K]3 years ago

5 0

Silt soil is usually more fertile than other types of soil, meaning it’s better for growing plants/crops

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A uniform steel rod has mass 0.400 kg and length 50.0 cm and is horizontal. A uniform sphere with radius

Eddi Din [679]

Explanation:

Center of gravity , Let center of rod is origin

= $\frac{(0.400*0)+(0.800*\frac{50}{2}+10)+ (0.200 *(-(25+5)) }{0.400+0.800+0.200}$

=15.71cm from the center of rod

5 0

3 years ago

Can someone pleaseee help me!!!

geniusboy [140]

Answer:You had a hard one. so for the 3 one the egg will not Evan float at all so no it will not

Explanation:a egg is a fragile thing that can not float.

7 0

4 years ago

If a 500kg elephant is sliding across a frictionless patch of ice, how much force is needed to keep the elephant from slowing do

Varvara68 [4.7K]

Answer:

Explanation:

The force needed to keep the elephant from slowing down is expressed as shown according to Newtons second law of motion.

Force = mass * acceleration due to gravity

Given

Mass of elephant = 500kg

acceleration due to gravity = 9.81m/s²

Force = 500*9.81

Force = 4905N

<em>Hence the force needed to keep the elephant from slowing down is 4905N</em>

5 0

3 years ago

You have a remote-controlled car that has been programmed to have velocity v⃗ =(−3ti^+2t2j^)m/s, where t is in s. At t = 0 s, th

DiKsa [7]

Answer:

The y-component of the car's position vector is 670m/s.

The x-component of the acceleration vector is -3, and the y-component is 40.

Explanation:

The displacement vector of the car with velocity

$\boldsymbol{v}= (-3t\boldsymbol{i}+2t^2\boldsymbol{j})m/s$

is the integral of the velocity.

Integrating $\boldsymbol{v}$ we get the displacement vector $\boldsymbol{d}$ :

$\boldsymbol{d}=(-\dfrac{3}{2}t^2\boldsymbol{i}+\dfrac{2}{3}t^3\boldsymbol{j} )$

Now if the initial position if the car is

$\boldsymbol{r}= (3.0\boldsymbol{i}+2.0\boldsymbol{j})$

then the displacement of the car at time $t$ is

$\boldsymbol{d(t)}= \boldsymbol{r+d}$

$\boxed{\boldsymbol{d(t)}=(-\dfrac{3}{2}t^2+3.0\boldsymbol{i}+\dfrac{2}{3}t^3+2.0\boldsymbol{j} )}$

Now at $t=10s$ , we have

$\boxed{\boldsymbol{d(t)}=(-147\boldsymbol{i}+670\boldsymbol{j} )}m$

The y-component of the car's position vector is 670m/s.

The acceleration vector is the derivative of the velocity vector:

$\boldsymbol{a(t)}=\dfrac{d\boldsymbol{v(t)}}{dt} =(-3\boldsymbol{i}+4t\boldsymbol{j})$

and at $t=10s$ it is

$\boldsymbol{a(t)}=(-3\boldsymbol{i}+40\boldsymbol{j})m/s^2$

The x-component of the acceleration vector is -3, and the y-component is 40.

5 0

3 years ago

Help! Plssssss 30 points!

Rashid [163]

The bigger the starting force, the further the distance moved by the car?

7 0

3 years ago