Answer:
kt 5.20 yes
Step-by-step explanation:
Students with D's / total students : 3 / (7 + 9 + 11 + 3 + 2) =
3 / 32 = 0.0937...to turn to a percent, multiply by 100 = 9.375....rounded =
9.4% <== ur probability
The slope-intercept form: y = mx + b
m - slope
b - y-intercept
We have 3x - 2y = 6 <em>subtract 3x from both sides</em>
-2y = -3x + 6 <em>divide both sides by -2</em>
y = 3/2 x - 3
slope: m = 3/2
y-intercept: b = -3
x-intercept for y = 0. Substitute:
3/2 x - 3 = 0 <em>add 3 to both sides</em>
3/2 x = 3 <em>multiply both sides by 2/3</em>
x = 2
<h3>Answer:</h3><h3>slope = 3/2</h3><h3>y-intercept = -3</h3><h3>x-intercept = 2</h3>
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y = 3/2 x - 3 it's the same function like first function.
Answer:
$37.85
Step-by-step explanation:
Here the price is $34.98 and there's an 8.2% tax on that. To obtain the after-tax amount due, multiply $34.98 by (1 + 0.082), or 1.082, obtaining:
1.082($34.98) = $37.85 (rounded to the nearest cent)
Answer:
We accept H₀ with the information we have, we can say level of ozone is under the major limit
Step-by-step explanation:
Normal Distribution
population mean = μ₀ = 7.5 ppm
Sample size n = 16 df = n - 1 df = 15
Sample mean = μ = 7.8 ppm
Sample standard deviation = s = 0.8
We want to find out if ozono level, is above normal level that is bigger than 7.5
1.- Hypothesis Test
null hypothesis H₀ μ₀ = 7.5
alternative hypothesis Hₐ μ₀ > 7.5
2.-Significance level α = 0.01 we will develop one tail-test (right)
then for df = 15 and α = 0,01 from t -student table we get
t(c) = 2.624
3.-Compute t(s)
t(s) = ( μ - μ₀ ) / s /√n ⇒ t(s) = ( 7.8 - 7.5 )*4/0.8
t(s) = 0.3*4/0.8
t(s) = 1.5
4.-Compare t(s) and t(c)
t(s) < t(c) 1.5 < 2.64
Then t(s) is inside the acceptance region. We accept H₀
