Answer:
t = 5.27 years
Explanation:
First of all, the formula for corrosion penetration rate is given as;
CPR = (KW)/(ρAt)
Where;
K = Constant dependent on exposed area A.
W - weight lost after time
t- time
ρ - density
A - exposed area
From the question;
W = 7.6kg or 7.6 x 10^(6) mg
CPR = 4 mm/yr
ρ = 4.5 g/cm³
Area = 800 cm²
K is a constant of 87.6cm
Making t the subject of the formula from the CPR equation, we obtain;
t = KW/(ρA(CPR))
t = (87.6 x 7.6 x 10^(6))/(4.5 x 800 x 4) = 46233.3 hours
The question wants the time in years.
So let's convert;
There are 8760 hours in a year.
Thus;
t = 46233.3/8760 = 5.27 years.
Answer: Partial pressures are 0.6 MPa for nitrogen gas and 0.4 MPa for carbon dioxide.
Explanation: <u>Dalton's</u> <u>Law</u> <u>of</u> <u>Partial</u> <u>Pressure</u> states when there is a mixture of gases the total pressure is the sum of the pressure of each individual gas:
The proportion of each individual gas in the total pressure is expressed in terms of <u>mole</u> <u>fraction</u>:
= moles of a gas / total number moles of gas
The rigid tank has total pressure of 1MPa.
molar mass = 14g/mol
mass in the tank = 2000g
number of moles in the tank: = 142.85mols
molar mass = 44g/mol
mass in the tank = 4000g
number of moles in the tank: = 90.91mols
Total number of moles: 142.85 + 90.91 = 233.76 mols
To calculate partial pressure:
For Nitrogen gas:
= 0.6
For Carbon Dioxide:
0.4
Partial pressures for N₂ and CO₂ in a rigid tank are 0.6MPa and 0.4MPa, respectively.
Answer:
A)
B)
Explanation:
Given data:
P-1 = 100 lbf/in^2
degree f
effeciency = 80%
from steady flow enerfy equation
where h1 and h2 are inlet and exit enthalpy
for P1 = 100 lbf/in^2 and T1 = 500 degree F
for P1 = 40 lbf/in^2
exit enthalapy h_2
from above equation
[1 Btu/lbm = 25037 ft^2/s^2]
b) amount of entropy
at
Answer:
Realigning the mirror
Explanation:
mirrors should be aligned to minimize blind spots, not look at the tires.
Answer: it would overload
Explanation: