Answer:
a. molecular interactions.
Explanation:
Conduction is thermal energy transfer by molecular interactions. Therefore, conduction involves the transfer of electric charge or thermal energy due to the movement of particles. When the conduction relates to electric charge, it is known as electrical conduction while when it relates to thermal energy, it is known as heat conduction.
In the process of heat conduction, thermal energy is usually transferred from fast moving particles to slow moving particles during the collision of these particles. Also, thermal energy is typically transferred between objects that has different degrees of temperature and materials (particles) that are directly in contact with each other but differ in their ability to accept or give up electrons.
Some examples of conductors include metal, steel, aluminum, copper, graphite, etc.
Hence, conduction is thermal energy transfer as a result of the movement of electrons and collision between the molecules of an object.
Answer:
try to 36v power and take 1a and intersect to 3
Explanation:
There are two rake angle types :
Positive rake
This is the case that occurs when looking from the inner side the face of the cutting tool slopes away from the cutting edge.
Negative rake
This is the case that occurs when the face of the cutting tool slopes away from the cutting edge at the outer side.
Increasing the positive rake angle means that the cutting tool will get sharper thus making the tool weaker. So, brittle material will form discontinuous chips and ductile material will form continuous chip. The tool life may also be reduced.
Increasing the negative rake angle means that the cutting tool will get blunt thus making the tool stronger. So, brittle material will form continuous chips. Results in higher temperature of the tool. Surface finish might increase.
Answer:
The final temperature in the vessel after the resistor has been operating for 30 min is 111.67°C
Explanation:
given information:
mass, m = 3 kg
initial temperature, T₁ = 40°C
current, I = 10 A
voltage, V = 50 V
time, t = 30 min = 1800 s
Heat for the system because of the resistance is
Q = V I t
where
V = voltage (V)
I = current (A)
t = time (s)
Q = heat transfer to the system (J)
so,
Q = V x I x t
= 50 x 10 x 1800
= 900000
= 9 x 10⁵ J
the heat transfer in the closed system is
Q = ΔU + W
where
U = internal energy
W = work done by the system
thus,
Q = ΔU + W
9 x 10⁵ = ΔU + 0, W = 0 because the tank is a well-insulated and rigid.
ΔU = 9 x 10⁵ J = 900 kJ
then, the energy change in the system is
ΔU = m c ΔT
ΔT = ΔU / m c, c = 4.186 J/g°C
= 900 / (3 x 4.186)
= 71.67°C
so,the final temperature (T₂)
ΔT = T₂ - T₁
T₂ = ΔT + T₁
= 71.67°C + 40°C
= 111.67°C
