Answer:
no values of x make the equation true
Step-by-step explanation:
Given that her work is correct, then the final step gives
4 = 5 ← meaningless
This indicates that the equation has no solution
1.) The interval of the value of x is from -5 to 1, inclusive. Remember that what is asked is the absolute value, thus the sign does not matter even if you have to subtract x from 5. Thus, the maximum value would be obtained if the x is smaller, which is 1. The minimum value is obtained when x=-5.
Absolute maximum value:
x = - 5f(-5) = ║5 - 7(-5)^2║ = ║-170║=
170Absolute minimum value:
x = 1f(1) = ║5 - 7(1)^2║ = ║-2║=
2
2.) The Mean Value Theorem (MVT) applies to functions that are continuous and differentiable on the closed and open interval of a to b, respectively. Since the function is a quadratic function, MVT can be applied. Then, this means that there is a value of c which is between a and b. This could be determined using this formula according to MVT:

The differentiated form would be f'(x) = -2x. Then,


Thus, x = -1, x = -1/2, and x=0 all lie in the function 4-x^2.
Answer:
See explanation below.
Step-by-step explanation:
First I'm going to find angle 2. Angle two plus 55 is equal to 115. 180-115=65. 65-55=10 Angle 2 = 10
Next, we can find angle 3. 55+10=65. 180-65=115. Angle 3 = 115
Angle 2 is equal to angle 5, angle 3 is equal to angle 6, and angle 4 is equal to 55.
Angle 5 = 10
Angle 4 = 55
Angle 6 = 115
Now we can find angle 8. 180-115=65. Angle 8 = 65
Angle 11 = 65
Angle 12 = 115
10+115=125 Angle 10 = 125
180-125 = 55 Angle 9 = 55
Angle 14 = 55
Angle 13 = 125
Rational numbers can be written as a fraction
Answer:
Srry I need points to see answers :(
Step-by-step explanation: