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puteri [66]
3 years ago
9

180 miles in 3 hours per 3 as a unit rate

Mathematics
2 answers:
boyakko [2]3 years ago
3 0
You drive 60 miles in 1 hour.
Roman55 [17]3 years ago
3 0
U would divide 180 by 3 and get 60.
60:1
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The nine ring wraiths want to fly from barad-dur to rivendell. rivendell is directly north of barad-dur. the dark tower reports
Verdich [7]

Velocity of the ring wraiths relative to the air:

\vec v_{W/A}=(v_{W/A}\cos45^\circ,v_{W/A}\sin45^\circ)=\left(\dfrac{v_{W/A}}{\sqrt2},\dfrac{v_{W/A}}{\sqrt2}\right)

The speed v_{W/A} is what we want to find - this is the speed at which the wraiths are flying in the air.

(Note: \vec v denotes velocity, while v denotes speed)

Velocity of air relative to the ground:

\vec v_{A/G}=((69\,\mathrm{mph})\cos180^\circ,(69\,\mathrm{mph})\sin180^\circ)=(-69,0)\,\mathrm{mph}

The ring wraiths want their trajectory to be due north, which means their velocity relative to the ground should be

\vec v_{W/G}=(v_{W/G}\cos90^\circ,v_{W/G}\sin90^\circ)=(0,v_{W/G})

To an observer on the ground, v_{W/G} is the speed at which the wraiths would appear to be moving in the air.

The relative velocities satisify

\vec v_{W/A}+\vec v_{A/G}=\vec v_{W/G}

\implies\begin{cases}\dfrac{v_{W/A}}{\sqrt2}-(69\,\mathrm{mph})=0\\\\\dfrac{v_{W/A}}{\sqrt2}=v_{W/G}\end{cases}

\implies v_{W/A}=69\sqrt2\,\mathrm{mph}\approx98\,\mathrm{mph}

5 0
3 years ago
Triangle A = 12 bh<br>Find the area<br>of the triangle<br>base 15in height 3in<br>A =​
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Answer:

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============================================================

Explanation:

The y intercept of the black f(x) curve is at (0,1)

The y intercept of the blue curve is at (0,4)

To go from y = 1 to y = 4, we add 3

So we shift 3 units up to go from the f(x) curve to the g(x) curve.

The value of k is 3, which corresponds exactly to the vertical shift. If we shifted down, then k would be negative.

8 0
3 years ago
F(x) = 10x2 + 8, evaluate f(-3).
OlgaM077 [116]

Answer:

98

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f(x) = 10x² + 8

= 10(-3)² + 8

= 10 (9) + 8

= 90 + 8

= 98

5 0
3 years ago
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