1*2*3*4+1=25=5^2 2*3*4*5+1=121=1^2 3*4*5*6+1=361=19^2
Answer:
The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Step-by-step explanation:
Let the random variable <em>X</em> denote the water depths.
As the variable water depths is continuous variable, the random variable <em>X</em> follows a continuous Uniform distribution with parameters <em>a</em> = 2.00 m and <em>b</em> = 7.00 m.
The probability density function of <em>X</em> is:

Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:

![=\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B5.00%7D%5Cint%5Climits%5E%7B5.00%7D_%7B2.25%7D%20%7B1%7D%20%5C%2C%20dx%5C%5C%5C%5C%3D0.20%5Ctimes%20%5Bx%5D%5E%7B5.00%7D_%7B2.25%7D%20%5C%5C%5C%5C%3D0.20%5Ctimes%20%285.00-2.25%29%5C%5C%5C%5C%3D0.55)
Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Answer:
intimately there are three types of angles a cute angle and angle between zero and 90° right angle and angle 90 degree angle of two angle and angle between 90 and 180 degree
Answer:
120 distinct results are possible if no child is to receive more than one gifts.
Step-by-step explanation:
When the order is not important, we use the combination formula:
is the number of different combinatios of x objects from a set of n elements, given by the following formula.

The order is said to be not important if for example, John receiving the Buffalo Bills jersey and then Laura receiving the Cleveland Browns jersey is the same as Laura receiving the Cleveland Browns jersey before John receives the Buffalo Bills jersey.
In this problem, we have that:
Combinations of 7 from a set of 10 elements. So


120 distinct results are possible if no child is to receive more than one gifts.
- Length (l) = 45 m
- Breadth (b) = 30 m
- We know, perimeter of a rectangle = 2(length + breadth)
- Therefore, perimeter of the rectangle
- = 2(I + b)
- = 2(45 + 30) m
- = 2 × 75 m
- = 150 m
- So, the distance travelled by Rubina
- = 4 × 150 m
- = 600 m
<u>Answer:</u>
<em><u>The </u></em><em><u>distance </u></em><em><u>travelled</u></em><em><u> </u></em><em><u>by </u></em><em><u>Rubina </u></em><em><u>is </u></em><em><u>6</u></em><em><u>0</u></em><em><u>0</u></em><em><u> </u></em><em><u>m.</u></em>
Hope you could get an idea from here.
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