Answer:
there would be 24 legs
Step-by-step explanation:
hope that helps
Answer:
Arlo's weight = 52.3 kg
Explanation:
Let Arlo be "x"
Then,
Arlo = x
Bert = x+20 (Because Bert is 20 heavier than Arlo)
Cassie = x+20-5 (Because Cassie is 5 lighter than Bert)
Donnie =
(Because Donnie is half of Bert's weight)
Average = 57
Step by step Calculations:
57 =
(The whole divided by 4 because the total people is 4)
57*4 = x + x + 20 + x + 20 - 5 + 
228 = 3x + 35 + 
228 - 3x - 35 = 
193 -3x = 
2(193 - 3x) = x + 20
386 - 6x = x + 20
386 - 20 = x + 6x
366 = 7x
x = 
x = 52.3 kg (corrected to 3 significant figures)
Therefore Arlo's weight is 52.3 kg
Answer:
System has equal number of unknowns and equations.
Manipulation easily yielded expressions for 4 of the 7 unknowns.
However it seems that the remaining 3 unknowns x,y,z are not fixed by the equations. Different combinations (x0,y0,z0) seem possible without violating the system equations.
Is this possible, or did I most probably make a mistake in counting degrees of freedom?
Step-by-step explanation:
Answer:
it is the first one
Step-by-step explanation: