The rate of change of a linear equation (first degree) is equivalent to the slope of a line. Slope is described as the vertical movement (rise) of the line over its horizontal counterpart (run). In determining the rate of change or slope (m) given 1 data point (x',y'), point-slope form is applicable. Point-slope form is: (y-y') = m (x-x'). Substitute the given point (-5,-1) in the equation. By substitution, [y-(-1)] = m [x-(-5)]. Re-arranging the equation, the rate of change or slope is, m = (y+1)/(x+5).
Answer:
y=x+12
Step-by-step explanation:
Well the slope is -4/-4 =1
We plug it into the formula, y=mx+b, but m=1
So it is y=1x+b
We know the points, so we plug y and x in which is:
-4=-4*4+b
-4=-16+b
b=12
So the point slope form of that is y=x+12
Answer:
d
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
46 - [(9 + 15 ÷ 5) × 3]
~We can simplify everythingusing PEMDAS
46 - [(9 + 3) × 3]
46 - [(12) × 3]
46 - 36
10
Best of Luck!
Answer:
x = 11
Step-by-step explanation:
Using Secants ad Segments Theorem we can say;
(x + 7) (7) = (15 + 6) (6)
7x + 49 = (21) (6)
7x + 49 = 126
7x = 77
x = 11
Hope this helps!
