All categories

3 years ago

A bus starts from rest. If it's velocity becomes 60 km/hr in 5 minutes, find

Physics

1 answer:

dimulka [17.4K]3 years ago

5 0

Answer:

5 miles

Explanation:

the bus is going 60km/hour meaning its going a mile a minute and it went on for 5 minutes meaning it went for 5 minutes/

You might be interested in

Two wires are identical, except that one is aluminum and one is tungsten. the aluminum wire has a resistance of 0.22 ω. what is

Margaret [11]

The resistance R of a piece of wire is given by
$R=\rho \frac{L}{A}$
where $\rho$ is the resistivity of the material, L is the length of the wire and A is its cross-sectional area.

Using this formula, and labeling with A the aluminum and with T the tungsten wire, we can write the ratio between $R_T$ (the resistance of the tungsten wire) and $R_A$ (the resistance of the aluminum wire):
$\frac{R_T}{R_A}= \frac{\rho_T \frac{L}{A} }{\rho_A \frac{L}{A} }$

the two wires are identical, so L and A are the same for the two wires and simplify in the ratio, and we get:
$R_T = \frac{\rho_T}{\rho_A} R_A$

By using the resistivity of the aluminum: $\rho_A=2.65 \cdot 10^{-8} \Omega m$ and the resistivity of the tungsten: $\rho_T = 5.6 \cdot 10^{-8} \Omega m$ m we can get the resistance of the tungsten wire:
$R_T = \frac{\rho_T}{\rho_A} R_A = \frac{ 5.6 \cdot 10^{-8} \Omega m}{2.65 \cdot 10^{-8} \Omega m} (0.22 \Omega) = 0.46 \Omega$

5 0

3 years ago

A solenoid 10.0 cm in diameter and 63.3 cm long is made from copper wire of diameter 0.100 cm, with very thin insulation. The wi

aliina [53]

Answer:

19559303watts

Explanation:

The field inside a solenoid is

B =µ0*N*I/h

where N is the number of turns, I the current in each turn, and h the length.

If the wire's diameter is d, then the number of turns is N = h/d so the equation becomes

B = µ0*I/d

I = B*d/µ0

B = 7.8*10^-3 T, d = 0.001 m, µ0 = 4*π*10^-7 H/m

I = 8*10^-3*0.001/(4*π*10^-17))

I = 6.366A

For power

We need to know ρ, the resistivity of the wire. The resistance of the coil R = ρ*L/A where L is the total wire length and A the area.

L = N*π*D, were D = diameter of the solenoid and N the no of turns. As above, N = h/d so L = h*π*D/d. The wire area is π*d²/4 so the resistance is

R = ρ*h*π*D/d*(π*d²/4) = 4*ρ*h*D/d³

The power is I²*R = (B*d/µ0)²*4*ρ*h*D/d³ = (B/µ0)²*4*ρ*h*D/d

For copper ρ = 16.8*10^-9 Ω-m and

D = 0.10 m, h = 0.722 m

P = (6.366 / 4 * π * 10^-7)^2 * 4 * 16.8 * 10 ^-9 * 0.722 * 0.1/0.001

P = 19559303watts

P = 20MW

7 0

4 years ago

Read 2 more answers

can you help me create a sketch of two different objects with one that has a greater density than the other?

sergey [27]

I don't know how good you are at sketching ... I'm terrible.
But you can put the point across in a dramatic way if you
can sketch a bowling ball and a basketball ... you'll need
to clearly identify them with the markings you sketch on
each ball.

They're the same shape and nearly the same size, but
there's a huge difference in their densities.

6 0

3 years ago

A 450.0 N, uniform, 1.50 m bar is suspended horizontally by two vertical cables at each end. Cable A can support a maximum tensi

bogdanovich [222]

Answer:

1) $W_{object} = 400 N$