Answer:
16 times that of car A
Explanation:
Moving objects have kinetic energy which is calculated using the formula:
E=(1/2)mv² where m is the mass of the object and v is its velocity.
For car A, kinetic energy =1/2×m×15²
=112.5m........................................i
For car B, the kinetic energy =1/2×m×60²
=1800m......................................ii
dividing ii by i we get
1800m/112.5m= 16.07
Therefore The kinetic energy of car B is 16.07 times that of car A
B is the answer! Because no one would be pushing the rock all the way down the hill it would just go down by itself by rolling!!
Hope i helped plz mark as brainlist and 5 star'!
<h2>
Answer:</h2>
0.126m
<h2>
Explanation:</h2>
According to Hooke's law, the force (F) acting on a spring to cause an extension or compression (e) is given by;
F = k x e -------------------(i)
Where;
k = the spring's constant.
From the question, the force acting on the spring is the weight(W) of the mass. i.e
F = W -----------------------(ii)
<em>But;</em>
W = m x g;
where;
m = mass of the object
g = acceleration due to gravity [usually taken as 10m/s²]
<em>From equation (ii), it implies that;</em>
F = W = m x g
<em>Now substitute F = m x g into equation(i) as follows;</em>
F = k x e
m x g = k x e ------------------(iii)
<em>From the question;</em>
m = m1 = 3.5kg
k = 278N/m
<em>Substitute these values into equation (iii) as follows;</em>
3.5 x 10 = 278 x e
35 = 278e
<em>Now solve for e;</em>
e = 35/278
e = 0.126m
Therefore, the distance the spring is stretched from its unstretched length (which is the same as the extension of the spring) is 0.126m
In the offensive role, the players try to get a goal.
In the defensive roll, The players try to protect the goal
Hoped this helped a little :)
