The sun would look like from earth if the entire photosphere were the same temperature as a sunspot then wouldn't see anything from Earth but darkness
The lowest layer of the sun is the photosphere. It is the outer layer of the sun. It is the deepest region of the luminous object. It is composed of convection cells which are called granules . The Sun's photosphere has a temperature between 4,500 and 6,000 K
Sunspots are areas where the magnetic field is about 2,500 times stronger than Earth's, much higher than anywhere else on the Sun. Because of the strong magnetic field, the magnetic pressure increases while the surrounding atmospheric pressure decreases.
Sunspots tend to occur in pairs that have magnetic fields pointing in opposite directions. A typical spot consists of a dark region called the umbra, surrounded by a lighter region known as the penumbra.
The sunspots appear relatively dark because the surrounding surface of the Sun (the photosphere) is about 10,000 degrees F, while the umbra is about 6,300 degrees F. Sunspots are quite large as an average size is about the same size as the Earth.
If the photosphere were of the same temperature as the sunspot, then we wouldn't see anything from Earth but darkness. We were only able to see and recognize the sunspot because it is surrounded by the visible photosphere.
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Answer:

Explanation:
The initial velocity of the ball is
u = +25.9 m/s (towards the wall)
while the final velocity of the ball is
v = -21.3157 m/s (away from the wall)
The time taken for the change in velocity to occur is
t = 0.0133 s
The acceleration can be calculated as the change in velocity divided by the time taken:

Substituting the numbers, we find:

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Ok so this is simple projectile motion problem.
if we have an object falling in free fall it is subject to gravity of -9.80m/s^2
so it says it takes 6 sec to fall and we know initial velocity was zero so we know that h=vt+1/2gt^2 so we get h=0+1/2*9.80*6^2 = 176.4m
so solving for final speed we get KE=PE = 1/2mv^2=mgh = 1/2v^2=gh so
v=sqrt(2*g*h) = sqrt(2*9.8*176.4m) = 58.8m/s final speed when it hits the ground
hope this helps you! Thanks!!