When it passes from one medium
Answer:
c. chloroacetate ion
Explanation:
The chloroacetic acid, ClCH₂CO₂H, is a weak acid with Ka = 1.36x10⁻³. When this weak acid is in solution with its conjugate base, ClCH₂CO₂⁻ (From sodium chloroacetate) a buffer is produced. The addition of a strong acid as the HCl produce the following reaction
HCl + ClCH₂CO₂⁻ → ClCH₂CO₂H + Cl⁻.
Where the acid reacts with the chloroacetate ion to produce more chloroacetic acid
That means, the HCl reacts with the chloroacetate ion present in the buffer solution
Right answer is:
<h3>c. chloroacetate ion</h3>
Answer:
3.0 L of NH₃
Solution:
The equation is as follow,
N₂ + 3 H₂ → 2 NH₃
According to equation,
67.2 L (3 mole) H₂ at STP produces = 44.8 L (3 mole) of NH₃
So,
4.50 L of H₂ will produce = X L of NH₃
Solving for X,
X = (4.50 L × 44.8 L) ÷ 67.2 L
X = 3.0 L of NH₃
